Answer:
A. 0.806 kN
B. 0.303 kN
Explanation:
<h3>A.</h3>
The kinetic energy of the ball is ...
KE = 1/2mv² = 1/2(0.206 kg)(18 m/s)² = 33.372 J
The work required to reduce this to zero over a distance of 4.14 cm is ...
W = Fd
F = W/d = (33.372 J)/(0.0414 m) = 0.806 kN
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<h3>B.</h3>
When the distance is 11 cm, the force is ...
F = (33.372 J)/(0.11 m) = 0.303 kN
To thaw a product requires it to undergo the process of
being subjected to latent heat of fusion. In this process, there is no change
in temperature however there is a change of phase from solid to liquid. What is
being thawed here actually is the frozen ice into liquid water which is in the
vegetables.
From the references, the latent heat of fusion of water
is:
Δ H = 333.55 kJ / kg
Therefore the amount of heat required to thaw the frozen
vegetable is:
Heat required = Δ H * m
Heat required = (333.55 kJ / kg) (0.450 kg)
Heat required = 150.10 kJ
In 1 kcal there is 4.184 kJ, therefore:
Heat required = 150.10 kJ (1 kcal / 4.184 kJ)
<span>Heat required = 35.87 kcal</span>
B. A machine changes the magnitude or direction of the force. Hope that helped.
They all end with suffix "-ide"
In short, Your Answer would be Option C
Hope this helps!