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Natalka [10]
3 years ago
9

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics
2 answers:
Sindrei [870]3 years ago
6 0
The answer is a i’m pretty sure, if i’m incorrect then i’m sorry but i’m sure that it’s a :)
belka [17]3 years ago
4 0

Answer:

A

Step-by-step explanation:

just wondering:

why do you ask questions multiple times?

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Did I use the right equations to find x?
EleoNora [17]

Answer:

first one yes

Step-by-step explanation:

second one its

39x+10=180

4 0
2 years ago
Read 2 more answers
(4n⁴-8n+4) - (8n²+4n⁴+1) <br> How do I simplify this expression?
Kobotan [32]

Answer:

-4n^4-4n^2-8n+3

Step-by-step explanation:

you combine the like terms

8 0
3 years ago
Whats the midpoint between 2 and 8​
ELEN [110]

Answer: 5

Step-by-step explanation:

8+2=10

10/2=5

7 0
3 years ago
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The tent shown below has fabric covering all four sides and the floor. What is the minimum amount of fabric needed to construct
fenix001 [56]

Answer:

I believe the answer is 152 ft

Step-by-step explanation:

On the side, you would find the area of the square (8x5=40). Then, you would find the area of the triangular front (6x4=24 divded by 2 so it's 12). There are two sides of each, so 24+80=104. Then, you dfind the aarea of the bottom square (6x8=48) and add them all together to make 152

6 0
3 years ago
Prove that sinxtanx=1/cosx - cosx
maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}

Taking the RHS, note

\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}

Remember that

\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)

Therefore,

\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}

Once

\dfrac{\sin(x)}{\cos(x)} = \tan(x)

Then,

\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)

Hence, it is proved

5 0
2 years ago
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