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3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics

2 answers:

Sindrei [870]3 years ago

6 0

The answer is a i’m pretty sure, if i’m incorrect then i’m sorry but i’m sure that it’s a :)

belka [17]3 years ago

4 0

Answer:

Step-by-step explanation:

just wondering:

why do you ask questions multiple times?

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Collin is building a deck on the back of his house. He has enough lumber for the deck to be 144 square feet. The length should b

joja [24]

Width = x
length = x+10

Area of deck = 144 square feet

Area = length * width

144 = x(x+10)

Solving for x in a quadratic:

x²+10x = 144
x²+10x-144 = 0

Factor:
(x+18)(x-8) = 0

Solving for x:
x = 8, x = -18

Dimensions cannot be negative, therefore x = 8, only.

Length = x + 10
Length = 18

Width = 8

4 0

2 years ago

Verona is solving the equation -3+4x=9. In order to isolate the variable term using the subtraction property of equality, which

DENIUS [597]

B. -3
Because -3 - (-3) = 0

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3 years ago

Read 2 more answers

Gill creates a model prism using 22 unit cubes. What is the volume of the prism?

jolli1 [7]

You could do V = b × H 2 × 11 = 22

8 0

2 years ago

Does a triangle with side lengths 7, StartRoot 80 EndRoot, and StartRoot 31 EndRoot from a right triangle?

AlladinOne [14]

Answer and Step-by-step explanation:

The sides we have are 7, $\sqrt{80}$ , and $\sqrt{31}$ .

The square root of 80 is less than 9 but greater than 8 (because $8^2$ is 64, $9^2$ is 81, and 80 is in between those two values), and the square root of 31 is definitely less than the square root of 80.

So, $\sqrt{80}$ is the longest side.

1) The square of $\sqrt{80}$ is: $(\sqrt{80} )^2=80$

2) The sum of the squares of the two shorter sides is:

$7^2+(\sqrt{31} )^2=49+31=80$

3) Since the square of the longest side is equal to the sum of the squares of the two shorter sides, by the Pythagorean Theorem, the triangle is a right triangles.

Hope this helps!

4 0

2 years ago

Read 2 more answers

A paper bag contains a mixture of 3 types of candy. there are 10 packs of fuzzy peaches, 7 packs of sour keys, and 3 packs of ne

sweet-ann [11.9K]

The probability that the person will be able to keep a pack of fuzzy peaches will be 0.25.

<h3>How to calculate the probability?</h3>

a. Based on the information given, the probability that the person will be able to keep a pack of fuzzy peaches will be:

= 10/(10 + 7 + 3) × 10/(10 + 7 + 3)

= 10/20 × 10/20

= 1/4

= 0.25

The probability that the person will be able to keep a pack of fuzzy peaches will be 0.25.

b. The probability to be able to keep any of the candy will be:

= (10/20 × 10/20) + (7/20 × 7/20) + (3/20 × 3/20)

= 100/400 + 49/400 + 9/400

= 158/400

= 0.395

The probability to be able to keep any of the candy will be 0.395.

c. The probability that you will not be able to keep any of the candy will be:

= (10/20 × 10/20) + (7/20 × 13/20) + (3/20 × 17/20)

= 100/400 + 91/400 + 51/400

= 242/400

= 0.605

The probability that you will not be able to keep any of the candy will be 0.605.

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

6 0

2 years ago