Answer:
-4ctv² + 10xyz - 9
Step-by-step explanation:
(2 + 5xyz - 6tv²c) - (11 - 5yxz - 2ctv²)
2 + 5xyz - 6tv²c - 11 + 5yxz + 2ctv²
-4ctv² + 10xyz - 9
I hope this helps!
Answer:
ok friend
Step-by-step explanation:
In all these expressions you have a power of a power.
You can solve them simply multiplying the exponents.
Remember that any quantity raised to the zero is equal to 1.
.
11) (n^4)^8 = n^(4×8) = n^32
13) (q^10)^10 = q^(10×10) = q^100
15) (x^3)^-5 = x^[3×(-5)] = x^(-15)
17) (z^8)^0z^5 = z^(8×0) z^5 = z^0 z^5 = 1×z^5 = z^5
<span>
19) (c^3)^5(d^3)^0 = c^(3</span>×5) d^(3×0) = c^15 d^0 = c^15×1 = c^15
I'm going to need more information before I can answer.
