The height of a building is 58.08 meters if the angle is 71 degree and the distance between A and B is 20 meters.
<h3>What is trigonometry?</h3>
Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.
We have:
Angle = 71 degree
Distance between A and B = 20 meters
Let's suppose the height of the building is x meters.
From the right angle triangle applying the tan ratio:
tan71 = x/20
x = 58.08 meter
Thus, the height of a building is 58.08 meters if the angle is 71 degree and the distance between A and B is 20 meters.
Learn more about trigonometry here:
brainly.com/question/26719838
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Answer:
and 
Step-by-step explanation:
Given
See attachment for complete question
Required
Determine the equilibrium solutions
We have:


To solve this, we first equate
and
to 0.
So, we have:


Factor out R in 

Split
or 
or 
Factor out W in 

Split
or 
Solve for R


Make R the subject


When
, we have:




Collect like terms

Solve for W




When
, we have:



Collect like terms

Solve for R


So, we have:

When
, we have:





So, we have:

Hence, the points of equilibrium are:
and 
Sorry can see good in the pic maybe next time
Sorry
6x-2=5x+29
6x-5x-2=29
x-2=29
x=31
The answer would be 2.16.
This is because the two negatives would cancel each other out when multiplying. This would basically make the question

.
Now 3.3 is definitely not less than 2.4, so the answer would be 2.16