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Pepsi [2]
3 years ago
10

State the valency of Al in Al²03​

Chemistry
1 answer:
dusya [7]3 years ago
4 0

Answer: Valency of Al in Al_2O_3 is +3.

Explanation:

The capacity of an element to gain or lose electrons is called valency of the atom or element.

The valency of oxygen is -2 is the compound Al_2O_3  and let the valency of Al is x over here.

Therefore, valency of x will be calculated as follows.

2x + \times 3(-2) = 0 (as the charge on compound is 0)

2x - 6 = 0

x = +3

Therefore, valency of Al in Al_2O_3 is +3.

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Rank the following aqueous solutions in order of increasing<br> (c) freezing point;
saveliy_v [14]

0.01 m AgNO_{3} < 0.03 m CuSO_{4}< 0.04 m urea

As molal concentration rises, so does freezing point depression. It can be expressed mathematically as ΔTf = Kfm.

<h3>What is Colligative Properties ?</h3>
  • The concentration of solute particles in a solution, not the composition of the solute, determines a colligative properties .
  • Osmotic pressure, boiling point elevation, freezing point depression, and vapor pressure reduction are examples of ligand-like properties.
<h3>What is freezing point depression?</h3>
  • When less of another non-volatile material is added, the temperature at which a substance freezes decreases, a process known as Freezing-point depression.
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Learn moree about Colligative Properties here:

brainly.com/question/10323760

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5 0
2 years ago
If a medicine ball in a gym has a mass of 4.0 Kg, what is its weight?
Temka [501]
I believe your answer will be 40
7 0
3 years ago
Read 2 more answers
What is the mass of a 500.00 mL sample of seawater with a density of 1.025 g/mL?
iragen [17]

Answer:

Mass of seawater = 512.5 gram

Explanation:

Given:

Volume of seawater = 500 ml

Density of seawater = 1.025 g/ml

Find:

Mass of seawater

Computation:

Mass of seawater = Volume of seawater × Density of seawater

Mass of seawater = 500 × 1.025

Mass of seawater = 512.5 gram

7 0
4 years ago
Seawater, which covers the majority of the earth, is composed primarily of molecules of H2O and equal numbers of Na ions and Cl-
Vsevolod [243]

Explanation:

Species present are H_{2}O(l), Na^{+}(aq) and Cl^{-}(aq). Now, we will calculate the number of componenets present as follows.

                C = n - E

where,   E = number of independent equations

              n = number of phases present

Therefore, we will calculate the number of components as follows.

                        C = 3 - 1

                            = 2

Since, sodium chloride (NaCl) will tend to form a homogeneous mixture in water. Therefore, phase will be equal to 1.

Therefore, it means that there are two components present in one phase.  

5 0
3 years ago
What temperature would be required to keep 0.895mol of gas in a 28.6L tank at a pressure of 0.500atm?
True [87]

Answer:

The temperature would be 194, 8 K.

Explanation:

We use the formula:

PV=nRT --> T=PV/nR

T= 0,500 atm x 28, 6 L/ 0,895 mol x 0,082 l atm /K mol

<em>T= 194,8494345 K</em>

3 0
4 years ago
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