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sertanlavr [38]
3 years ago
6

What temperature would be required to keep 0.895mol of gas in a 28.6L tank at a pressure of 0.500atm?

Chemistry
1 answer:
True [87]3 years ago
3 0

Answer:

The temperature would be 194, 8 K.

Explanation:

We use the formula:

PV=nRT --> T=PV/nR

T= 0,500 atm x 28, 6 L/ 0,895 mol x 0,082 l atm /K mol

<em>T= 194,8494345 K</em>

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Calculate the solubility of carbon dioxide in water at an atmospheric pressure of 0.400 atm (a typical value at high altitude).A
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Answer:

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Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

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K_H = Henry's constant = 3.50\times 10^{-2}mol/L.atm

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