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TiliK225 [7]
4 years ago
5

If volume is increased, the number of collisions per second... decreases or increases?

Chemistry
1 answer:
Kaylis [27]4 years ago
4 0

Answer:

if volume is increased, the number of collisions per second decreases.

Explanation:

volume is inversely proportional to pressure. Increase in volume leads to decrease in pressure and decrease in volume leads to increase in pressure.

if the pressure is high, it leads to increase in the number of collisions. If the pressure is low, it leads to decrease int he number of collisions.

therefore since volume is inversely proportional, when volume is increased, the pressure decreases and thus the number of collisions decreases.

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Answer:

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Explanation:

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For the reaction N2(g) + O2(g)2NO(g) H° = 181 kJ and S° = 24.9 J/K G° would be negative at temperatures (above, below) K. Enter
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ΔG deg will be negative above 7.27e+3 K.

<u>Explanation:</u>

  • The ΔG deg with the temperature can be found using the formula and the formula is given below
  • ΔG deg = ΔH deg - T ΔS deg
  • Given data, ΔH deg = 181kJ and ΔSdeg=24.9J/K
  • -T ΔS deg will be always negative and ΔG deg = ΔH deg  will  be  positive and ΔG deg will be negative at relatively high temperatures and positive at relatively low temperatures
  • solving the equation and substitute  ΔGdeg=0
  • ΔGdeg = ΔHdeg - T ΔSdeg
  • T= ΔHdeg/ΔSdeg
  • T=181 kJ / 2.49e-2 kJK-1
  • By simplification we get
  • T=7.27 × 10^3 K.
  • Therefore, Go will be negative above   7.27 × 10^3 K
  • Since ΔG deg = -RT lnK, when ΔGdeg < 0, K > 1 so the reaction will have K > 1 above 7.27 × 10^3 K.
  • ΔG deg will be negative above 7.27e+3 K.

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7 0
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