Answer:
There is no map
Explanation:
Without the map, there is no way of answering this question.
Answer The value of
and
is, 40.79 kJ and 37.7 kJ respectively.
Explanation :
Heat released at constant pressure is known as enthalpy.
The formula used for change in enthalpy of the gas is:

Now we have to calculate the work done.
Formula used :

where,
w = work done = ?
P = external pressure of the gas = 1 atm
= initial volume = 
= final volume = 
Now put all the given values in the above formula, we get:


Now we have to calculate the change in internal energy.



Thus, the value of
and
is, 40.79 kJ and 37.7 kJ respectively.
Answer:
.926 moles
Explanation:
Rounding :
H2 0 = 18 gm/mole
50 gm would then be 50 / 18 = 2.7777 moles of water
every two moles of 2 C6H6 produces 6 moles of water
2.7777/6 * 2 = .926 moles
Answer:
[O₃]= 8.84x10⁻⁷M
Explanation:
<u>The photodissociation of ozone by UV light is given by:</u>
O₃ + hν → O₂ + O (1)
<u>The first-order reaction of the equation (1) is:</u>
(2)
<em>where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration </em>
<u>We can get the following expression of the </u><u>first-order integrated law</u><u> of the reaction (1), by resolving the equation (2):</u>
(3)
<em>where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration</em>
We can calculate the initial ozone concentration using equation (3):
So, the ozone concentration after 10 days is 8.84x10⁻⁷M.
I hope it helps you!