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anygoal [31]
2 years ago
7

When solving 325 ÷ 5, you end up with the partial quotients of: 10 + 10 + 10 + 10 + 10 + 10 + 5

Mathematics
1 answer:
kolezko [41]2 years ago
7 0

Answer:

130

Step-by-step explanation:

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The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?
Ghella [55]

Let the four consecutive integers be

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ATQ, Their sum is 18

\sf \: x + x + 1 + x + 2 + x + 3 = 18

\sf \: 4x + 1 + 2 + 3 = 18

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\sf4x = 18 - 6

\sf4x = 12

\boxed{ \mathfrak{x = 3}}

<h3>Now,</h3>

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  • 4th number = x+3 = 3+3 = 6

<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

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Brrunno [24]

We have to solve this quadratic equation n^{2}+n=56 for n to get <em>which figure has 56 blocks</em>.

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For middle term factorization, we need <em>two numbers that multiplied gives us -56 and added gives us 1 (coefficient of n).</em>

<em>Such two numbers are </em><em>8</em><em> and </em><em>-7</em><em>. We can now write,</em>

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<u><em>"There is no negative figure number possible, so we disregard -8"</em></u>

Our answer is 7.


ANSWER: The 7th figure has 56 blocks.


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The answer is A. Slope is rise/run. According to the graph, you can trace out and see that it rises 1 and goes to the right 4 times. This means that it has a positive slope of 1/4. And the line crosses the y intercept at y = 3

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The probability of drawing a jack from a standard 52 card deck is 7.69%
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