Question

Need Help this is due in 30 minutes!

Answer 1

Answer:

E

Step-by-step explanation:

Since all the numbers are hundredths decimals, let multiply by the power of 2 of the base 10. So let multiply the equation by

$10 {}^{2}$

So our new equation is

$3 3{x}^{2} + 71x - 14 = 0$

Solve by AC method

$ac = - 462$

$b = 71$

We must think of two numbers that

Multiply to -462 and Add to 71. Set up equation

The numbers are 77 and -6.

So our new equation is

${33x}^{2} + 77x - 6x - 14 = 0$

Solve by factoring by grouping

$(33 {x}^{2} + 77x) - (6x - 14)$

Factor out 11 for the first equation

$11x(3x + 7) - 2(3x + 7)$

So our factors are

$(11x - 2)(3x + 7)$

Set each equal to zero

$11x - 2 = 0$

$11x = 2$

$x = \frac{2}{11}$

$3x + 7 =$

$3x = - 7$

$x = \frac{ - 7}{3}$