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-Dominant- [34]
3 years ago
13

The point (3, -4) is on the terminal side of angle Θ, in standard position. What are the values of sine, cosine, and tangent of

Θ?
Mathematics
1 answer:
julia-pushkina [17]3 years ago
7 0

3=x

-4=y

a { }^{2}  + b {}^{2}  = c {}^{2}

3 {}^{2}  + 4 {}^{2}  = c {}^{2}

\sqrt{} 25 =  \sqrt{c {}^{2} }

5 = c

sin0= 4/5

cos0=3/5

tan0=4/3

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Answer= -54



-2(bx-5)=16

If b is 3, then it changes to -2(3x-5)=16

We want to find x, right? Then we must do -2•3x and -2(-5). The result would be -6x and 10.

Then again, the equation would change -6x+10=16
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And then x would be 1


Please tell me what I did wrong and if it is wrong, comment on this and I’ll fix my mistake!^^

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