Given:
Consider the equation is:

To prove:
by using the properties of logarithms.
Solution:
We have,

Taking left hand side (LHS), we get

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

![[\because \log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20x%5En%3Dn%5Clog%20x%5D)

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

Hence proved.
Hello from MrBillDoesMath!
Answer: f(x) = (2/3)*x -3 -- which is not a provided answer..
Discussion:
We are given that y + 7 = (2/3) * (x + 6). Multiply out the right hand side:
y + 7 = (2/3) * x + (2/3) * 6 = (2/3) *x + 12/3
= (2/3)*x + 4
Subtract 7 from both sides:
y + 7 - 7 = (2/3)*x + 4 - 7
or
y = (2/3)*x -3
Thank you,
MrB
y + 7= 2/3(x+6)
Prime factorization of 5·2·5=5^2·2
Answer:
yoo
Step-by-step explanation:
All you do is add a zero on the end of this to make it to the nearest hundreth: 34.8(0)
That means that this is the correct order: 34.8, 36.43, 36.29 or Option B