Answer:
.0172 mole of CO2
Explanation:
PV = nR T n = number of moles V = .5 liter
R = gas constant = .082057 L atm/(k mole)
T needs to be in Kelvin = C + 273.15
.868 * .5 = n * .082057 * ( 35 + 273.15)
n = .0172 moles
Explanation:
Molecular mass of NO2= 14+16×2=46
1 mole NO2 = 46 gm of NO2
9.4 moles of NO2= 46×9.4 gm= 432.4 gm NO2.
Balanced equation:
4 FeS₂ + 11 O₂ --> 2 Fe₂O₃ + 8 SO₂
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Find the limiting reactant (the one that produces the least amount of product) :
(73.5 g FeS₂) * (1 mole FeS₂ / 119.975 g FeS₂) * (2 moles Fe₂O₃ / 4 moles FeS2) * (159.6882 g Fe₂O₃ / 1 mole Fe₂O₃)
= 48.9 g Fe₂O₃ …………. to 3 sig figs
(44 g O₂) * (1 mole O₂ / 31.9988 g O₂) * (2 moles Fe₂O₃ / 11 moles O₂) *
(159.6882 g Fe₂O₃ / 1 mole Fe₂O₃)
= 40 g Fe₂O₃ ………………. to 2 sig figs
O₂ is the limiting reactant and the theoretical yield is 44 g Fe₂O₃
Answer:
degree of hotness or coldness measured on a definite scale. the degree of heat that is natural to the body of a living being. abnormally high body heat running a temperature.
Explanation:
