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katovenus [111]
1 year ago
5

a plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. what is its water potential? show your work if i

t is placed in a solution with a water potential of -1.0 what will happen to this plant cell
Chemistry
1 answer:
sukhopar [10]1 year ago
5 0

A plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. Its water potential is -2 bar. The cell will gain water or swell.

<h3>What is Water Potential ?</h3>

Water Potential is the potential energy of water in a system per unit volume relative to pure water , when both pressure and temperature are kept same. Water potential is never positive. It is expressed in kPa (Kilopascals). The symbol of water potential is ψ.

<h3>How to find the Water Potential ?</h3>

To find the water potential use this formula

\Psi = \Psi_{s} + \Psi_{p}

where,

ψ = Water Potential

\Psi_{s} = Solute Potential

\Psi_{p} = Pressure potential

Now put the value in above expression we get

\Psi = \Psi_{s} + \Psi_{p}

   = -2.0 + 0.0

   = - 2 bar

Thus from the above conclusion we can say that A plant cell has a solute potential of -2.0 bars and pressure potential of 0.0. Its water potential is -2 bar. The cell will gain water or swell.

Learn more about the Water Potential here: brainly.com/question/23855783

#SPJ1

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How many grams of ammonium chloride (gram formula mass= 53.5 g) are contained in .500 L of a 2.00 M solution?
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Answer:

53.5g of NH4Cl

Explanation:

First, we need to obtain the number of mole of NH4Cl. This is illustrated below:

Volume = 0.5L

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Mole = Molarity x Volume

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Now, let us convert 1mole of NH4Cl to gram. This is illustrated below:

Molar Mass of NH4Cl = 53.5g/mol

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2 years ago
8. A 220 mL sample of helium gas is in a cylinder with a movable piston at 105 kPa and 275K. The piston
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The sample has a new pressure of 274kPa. If at 105 kPa and 275K, a 220 mL sample of helium gas is contained in a cylinder with a moving piston. The sample is pushed till it has a 95.0 mL volume and 310K .

The macroscopic characteristics of ideal gases are related by the ideal gas law (PV = nRT). A gas is considered to be perfect if its particles (a) do not interact with one another and (b) occupy no space (have no volume). Where P= pressure  V= volume and T = temperature.

From ideal gas equation

P₁V₁/T₁ =P₂V₂/T₂

105×220÷275 = P₂ ×95÷310

P₂= (105×220×310)÷(275×95)

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To know more about Ideas gas equation

brainly.com/question/28837405

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You need to produce a buffer solution that has a pH of 5.31. You already have a solution that contains 10. mmol (millimoles) of
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Answer:

37 mmol of acetate need to add to this solution.

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Acetic acid is an weak acid. According to Henderson-Hasselbalch equation for a buffer consist of weak acid (acetic acid) and its conjugate base (acetate)-

pH=pK_{a}(acetic acid)+log[\frac{mmol of CH_{3}COO^{-}}{mmol of CH_{3}COOH }]

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