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Jet001 [13]
3 years ago
14

What is the principal reason we must consider the uncertainty principle when discussing electrons and other subatomic particles

but not when discussing our macroscopic world?
Chemistry
1 answer:
Pie3 years ago
3 0
Here is the correct answer of the given question above. The principal reason that we must consider the uncertainty principle when discussing electrons and other subatomic particles, but not when discussing our macroscopic world is that photons of only certain allowed frequencies can be absorbed or emitted as the electron changes energy state. Hope this answer helps.
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A. Draw a graph that shows the relative concentration of BTB from the center of the
rosijanka [135]

Answer:

did you get the answer???

Explanation:

I really need help

6 0
3 years ago
How much energy is used to melt 44.33 g of solid oxygen?
Nutka1998 [239]

Answer:

Q1 = C * m * dT

Q2 = Qm * m

Qtotal = Q1 + Q2

Q1 - is amount of energy you need to apply to heat oxygen from the current temperature till you reach the melting temperature. Only if the oxygen is below to melting temperature.

C - is calorific capacity of oxygen -- better look at tables, it is a constant value

m - is the amount of oxygen, we will use moles because the other data shows moles, but could be grams, kg, etc.

dT - is the diference of temperatures between the current and the melting one. The melting temperature is constant and you can find it on tables, then (Tm - To)

Q2 is the amount of energy you have to add to melt oxygen once the oxygen has reached the melting temperature (Tm)

Qm is a constant value you could find on tables, depends on the mass of oxygen and is due to internal processes as changes in atomic distributions

If the oxygen is initially at melting temperature (melting point) you only need to know Q2, as dT = 0

I will do an example for you, but in future you should provide data of constants, it takes very long to find them in books or internet.

Data from tables

Tm =  54.36 K

C = 29.378 J/mol K this is at 25 C (or 298 K), is not really correct, you should look at its value at less than 54.36 K, but you can use it here.

Qm = 0.444 kJ/mol

Problem -- you have 44.33g of Oxygen -- Molecular weight of O2 is 32 g/mol

So you have 44.33/32 = 1.385 moles of oxygen

a) if oxygen is already at melting temperature: you only have to melt it

Qtotal = Q1 + Q2 = [0 (dT = 0) + Qm * m] = 0.444 * 1.385 = 0.615 kJ = 615 J

b) supposing an initial temperture of 50 K: now you have to heat oxygen till melting temperature and then melt it.

Q1 = C * m * dT = 29.378 * 1.385 * (54.36 - 50) = 177.442 J

Q2 = Qm * m = 615 J

Qtotal = 177.442 + 615 = 792.44 J

Explanation:

4 0
2 years ago
Read 2 more answers
The bond order denotes:_____.1. the order of filling of bonding vs. antibonding orbitals. 2. the pattern in which Lewis dot stru
tiny-mole [99]

Answer:

an estimate of the strength of a bond.

Explanation:

The bond order is given as;

1/2(number of bonding electrons - number of anti bonding electrons)

The bond order tells us about the strength of bond. As the bond order increases, so does the strength of the bond because atoms involved in bonding come closer to each other as the bond length decreases.

Hence, bond order is an index of bond strength. Triple bonds are stronger than double bonds which are stronger than single bonds.

6 0
3 years ago
Lakshmi has a sample of ammonium nitrate (NH4NO3) that has a mass of 40. 10 g. She knows that the molar mass of NH4NO3 is 80. 04
nexus9112 [7]

Moles are an estimation of the smallest unit of the molecules and the atoms in a sample. The moles of ammonium nitrate in a sample are 0.5010 moles.

<h3>What are moles?</h3>

Moles are calculated by dividing the mass of the substance in gm by that of the molar mass in gram per mole.  

Given.

Mass of ammonium nitrate = 40.10 gm

The molar mass of ammonium nitrate = 80. 0432 g/mol

Moles of ammonium nitrate are calculated as:

\begin{aligned}\rm moles &= \rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{40.10}{80.0432}\\\\&= 0.5010 \;\rm mol\end{aligned}

Therefore, moles of ammonium nitrate present is option d. 0.5010 moles.

Learn more about moles here:

brainly.com/question/2396149

8 0
2 years ago
Given that there are 6.02×1023 particles in 1.00 mole, how many h2o molecules are in 0.17 mole h2o?
Marizza181 [45]
1 mol ------------ 6,02×10²³
0,17 mol ------- X
X =(0,17×6,02×10²³)/1
X = 1,0234×10²³ molecules H₂O

:•)
6 0
3 years ago
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