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Jet001 [13]
3 years ago
14

What is the principal reason we must consider the uncertainty principle when discussing electrons and other subatomic particles

but not when discussing our macroscopic world?
Chemistry
1 answer:
Pie3 years ago
3 0
Here is the correct answer of the given question above. The principal reason that we must consider the uncertainty principle when discussing electrons and other subatomic particles, but not when discussing our macroscopic world is that photons of only certain allowed frequencies can be absorbed or emitted as the electron changes energy state. Hope this answer helps.
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Se valoró una alícuota de 10ml de HCl con NaOH AL 0.0548M de la cual se gastó 17.9ml. La concentración molar del ácido es:
Ymorist [56]

Answer:

se lonh hion ffyuk jlngvn

7 0
3 years ago
Determine the ground-state electron configuration for each of the following elements: A. chlorine ______________________________
ki77a [65]

In ground-state electron configuration, the<u> principal quantum number</u> (n), <u>the orbital</u> (s, p, d, or f), and the total number of <u>electrons</u> are used to represent electron configurations.

Case 1 Ground-state electron configuration of elements.

A) Chlorine: 1s²2s²2p^{6}3s²3p^{5}

B) Cesium: 1s² 2s²2p⁶ 3s²3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 6s¹

C) Vanadium: 1s²2s²2p⁶3s²3p⁶3d³4s²

D) Rhenium: 1s² 2s² 2p⁶ 3s² 3p⁶3d¹⁰ 4s²4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁵ 6s²

Case 2 : Number of valence electron in atoms

A) Sn -Tin - Four valence electrons

B) La - Lanthanum - Three valence electrons

C) Mn - Manganese - Seven valence electrons

D) Zn- Zinc - Two valence electrons

Case 3 Ground-state electronic configuration of ions

A) Co⁺³ : 1s² 2s² 2p⁶ 3s² 3p⁶4s¹3d⁵

B) Mo⁺² : 1s² 2s² 2p⁶3s²3p⁶ 4s² 3d¹⁰ 4p⁶5s² 4d²

C) Ra⁺² : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 4f¹⁴ 5s² 5p⁶ 5d¹⁰ 6s² 6p⁶

D) I⁻ : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶

Learn more about Quantum numbers here brainly.com/question/2292596

#SPJ4

8 0
2 years ago
The mass spectrum of an unknown compound has a molecular ion peak with a relative intensity of 57.10% and an M+1 peak of 6.83%.
max2010maxim [7]

There are 11 Carbon atoms in the compound.

<u>Solution:</u>

Carbon atom count is the ratio of the M peak to the M+1 peak.

\text{ Number of Carbon atoms }=\frac{\text { Relative intensity of } M+1 \text { peak }}{0.011 \times \text { Relative tntensity of } M \text { peak }}

Here M peak is 57.10% and M+1 peak is 6.83%. On applying the values in the formula we get,

\frac{0.0683}{0.011\times0.571g} = 10.87\approx11

Therefore, the number of Carbon atoms in the compound are 11.

Refer the image attached below for a better understanding of M peak and M+1 peak.

The heaviest ion that has the greatest m/z value is said to be the molecular ion peak in mass spectrum.

6 0
4 years ago
Who uses holmium? I need to know for a science project.
Tanzania [10]

Answer:

Holmium can absorb neutrons, so it is used in nuclear reactors to keep a chain reaction under control. Its alloys are used in some magnets. Holmium has no known biological role, and is non-toxic. Holmium is found as a minor component of the minerals monazite and bastnaesite.

Explanation:

this is basically used in industries

7 0
3 years ago
Classify this chemical reaction:<br><br> 2 HNO3 (aq) + Sr(OH)2 (aq) → Sr(NO3)2 (aq) +2 H2O (l)
ad-work [718]

Answer:

This is not an answer its just to get points

7 0
3 years ago
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