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Jet001 [13]
2 years ago
14

What is the principal reason we must consider the uncertainty principle when discussing electrons and other subatomic particles

but not when discussing our macroscopic world?
Chemistry
1 answer:
Pie2 years ago
3 0
Here is the correct answer of the given question above. The principal reason that we must consider the uncertainty principle when discussing electrons and other subatomic particles, but not when discussing our macroscopic world is that photons of only certain allowed frequencies can be absorbed or emitted as the electron changes energy state. Hope this answer helps.
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Which molecule below has hydrogen bonding? Which molecule below has hydrogen bonding? H2 CH3CH2OH HCl CH4 all of the above
QveST [7]

Answer:

CH_3CH_2OH

Explanation:

Hydrogen bonding:-

Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.

Partially positive end of the hydrogen atom is attracted to partially negative end of these atoms which is present in another molecule. It is strong force of attraction between the molecules.

Thus, hydrogen must be linked to electronegative atom which is oxygen, fluorine and nitrogen which is in CH_3CH_2OH and thus, it will shown hydrogen bonding.

3 0
2 years ago
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AlekseyPX
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5 0
2 years ago
An Earth-like planet is 500 light years away why is this an Obstacle for a manned Space mission?
maxonik [38]

Answer:c the correct technology cannot support this mission

Explanation:

3 0
3 years ago
Read 2 more answers
. How many grams of NaOH would you need to make 450 mL of a 0.250 M NaOH solution
Stella [2.4K]
You have molarity and you have volume. Use the formula :
Molarity(M)= Moles(N)/Liter(L)            to get the solution. 
450 ml= .450 L
.250 = N/.450
N=.1125 moles of NaOH.
 And since you know the moles, use the molar mass to figure out the grams.
<span> (40g/mol NaOH) x (.1125 mol) =  
4.5g of NaOH.
</span>
Hope it helps. Good luck on chemistry.
7 0
3 years ago
A mixture of hydrochloric and sulfuric acids is prepared so that it contains 0.315 M HCl and 0.125 M H2SO4. What volume of 0.55
Xelga [282]

<u>Answer:</u> The volume of NaOH required is 402.9 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

  • <u>For HCl:</u>

Molarity of HCl solution = 0.315 M

Volume of solution = 503.4 mL = 0.5034 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

0.315M=\frac{\text{Moles of HCl}}{0.5034L}\\\\\text{Moles of HCl}=(0.315mol/L\times 0.5034L)=0.1586mol

  • <u>For sulfuric acid:</u>

Molarity of sulfuric acid solution = 0.125 M

Volume of solution = 503.4 mL = 0.5034 L

Putting values in equation 1, we get:

0.125M=\frac{\text{Moles of }H_2SO_4}{0.5034L}\\\\\text{Moles of }H_2SO_4=(0.125mol/L\times 0.5034L)=0.0630mol

As, all of the acid is neutralized, so moles of NaOH = [0.1586 + 0.0630] moles = 0.2216 moles

Molarity of NaOH solution = 0.55 M

Moles of NaOH = 0.2216 moles

Putting values in equation 1, we get:

0.55M=\frac{0.2216}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.2216}{0.55}=0.4029L=402.9mL

Hence, the volume of NaOH required is 402.9 mL

6 0
3 years ago
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