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cricket20 [7]
3 years ago
10

What is the mass of a 300 ml sample of gaseous hydrogen chloride at 2.0 atm and 30c?

Chemistry
1 answer:
kap26 [50]3 years ago
3 0
Use PV = nRT
(2 atm)(.3 liters) = n(8.314 mol*K)(303°K)

.6 = n(2519.142)

Divide by 2519.142

n = .00023818 mols of HCl * 36.46g of HCl/ 1 mol of HCl

Grams of HCl = 0.00868
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A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental
OleMash [197]

Answer:

the empirical (lowest raios) is

C2H4Cl    

Explanation:

A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental analysis, it was determined that the compound is composed of 24.27% carbon.

What is the empirical formula of this compound?

the compound has ONLY C, H, and Cl

the % Cl  = 100% - 24.27% -4.03% = 71.7%

in 100 gm, there are 71.7 gm Cl, 24.27 gm C, and 4.03 gm H

the number of moles are Cl=71.7/70.91 =1.01= ~ 1

                                          C = 24.27/12.0 = 2.02 =~ 2

                                           H = 403/1.01 = 3.97 =~   4

so   the empirical (lowest raios) is

C2H4Cl      

                                 

                               

3 0
2 years ago
15.630 g milk chocolate bar ks found to contain 9.815g of sugar. how many milligrams of sugar does the bar contain?
sleet_krkn [62]
Well there are 1,000 milligrams in 1 gram so 9.815 grams of sugar is equivalent to 9,815 milligrams of sugar. So a bar of milk chocolate contains 9,815 milligrams of sugar.
3 0
3 years ago
Read 2 more answers
1.5mol C3H8 from C3H8+5O2-->3CO2+4H2O .how many grams of carbon dioxide are produced
koban [17]

Answer:

\large \boxed{\text{200 g CO}_{{2}}}

Explanation:

We will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

Mᵣ:                                 44.01

            C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

n/mol:    1.5

1. Calculate the moles of CO₂

The molar ratio is 3 mol  CO₂:1 mol C₃H₈

\rm  \text{Moles of CO}_{2} = \text{1.5 mol C$_{3}$H}_{8} \times \dfrac{\text{3 mol CO}_{2}}{\text{1 mol C$_{3}$H}_{8}} =\text{4.5 mol CO}_{2}

2. Calculate the mass of CO₂.

\text{Mass of CO}_{2} = \text{4.5 mol CO}_{2}  \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO$_{2}$}} = \textbf{200 g CO}_{\mathbf{2}}\\\text{The reaction will form $\large \boxed{\textbf{200 g CO}_{\mathbf{2}}}$}

3 0
2 years ago
Explain why need modifications about temperature and keep pressure atom
Yuri [45]

Answer:

The pressure law states that for a constant volume of gas in a sealed container the temperature of the gas is directly proportional to its pressure. ... This means that they have more collisions with each other and the sides of the container and hence the pressure is increased.

7 0
3 years ago
A mixture was found to contain 1.05 g if silicone dioxide, 0.69 g cellulose, 1.82 g of calium carbonate. what percent of calcium
djverab [1.8K]
1,05+ 0,69 + 1,82 = 3,56g of mixture

%CaCO₃: 1,82/3,56×100% = 0,5112×100% = 51,12%
5 0
2 years ago
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