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vichka [17]
3 years ago
6

For an acute angle θ, the equation sin(θ)=cos(6) is true. What is the value of θ? Show or explain your answer

Mathematics
1 answer:
sweet [91]3 years ago
4 0

Answer:

\theta= 84

Step-by-step explanation:

Given

\sin(\theta) = \cos(6)

Required

Find \theta

In trigonometry,

If \sin(\theta) = \cos(\alpha), then

\theta + \alpha = 90

So, in this case:

\theta + 6= 90

Subtract 6 from both sides

\theta + 6-6= 90-6

\theta= 90-6

\theta= 84

<em>Hence, the value of </em>\theta<em> is 84 degrees</em>

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Find the measure of
yaroslaw [1]

Answer:

∠ HGL = 73°

Step-by-step explanation:

KL is a midsegment of the triangle and is parallel to HG, then

∠ KLJ = ∠ HGL ( corresponding angles ), so

9x - 62 = 5x - 2 ( subtract 5x from both sides )

4x - 62 = - 2 ( add 62 to both sides )

4x = 60 ( divide both sides by 4 )

x = 15

Thus

∠ HGL = 5x - 2 = 5(15) - 2 = 75 - 2 = 73°

4 0
3 years ago
ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°, what is the value of m?
Digiron [165]

Answer:

The correct answer is option B.  17

Step-by-step explanation:

It is given that, ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°

To find the value of m

From the figure we can see that, triangle WYZ is an isosceles  triangle.

ZW = ZY

Then <YXZ = <WXZ = 90°

It is given ∠YXZ  = (6m – 12)°

(6m – 12)° =  90°

6m = 90 + 12  = 102

m = 102/6 = 17

Therefore the value of m = 17

The correct answer is option B.  17

8 0
2 years ago
Read 2 more answers
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
Does anybody know what 2+3 is
Phoenix [80]
The answer is 5 you can also use your fingers no I’m not calling you dumb I’m just saying you can
4 0
3 years ago
The shorter leg of a right triangle is 8 less than the hypotenuse. The longer leg
CaHeK987 [17]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
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