The first number would be represented by x, the second as
x+2 and the third as
x+4. Together they equal 117, so x+x+2+x+4= 117. You can sinplify that to equal 3x+6=117. You then solve for x (subtract the 6 from both sides to get 3x=111, and then divide both sides by 3 and you get x=37). The three numbers would be 37,39, and 41. The smallest is 37.
Answer:
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Step-by-step explanation:
As = A5-1+ 500 ;) let me know if u need anything else
6x + 1 = 2x + 10 + 79
6x + 1 = 2x + 89
4x = 88
x = 22
Let X and Y represent the midpoints of AC and EB, respectively. We are given
AB = 36
XY = 30
We know that AX +XY +YB = AB = 36, so AX+YB = 36-30 = 6. We also know that AX = XC and EY = YB, so XC+EY = AX+YB = 6.
Since XC +CE + EY = XY = 30, and XC+EY = 6, we must have CE = 30-6 = 24.
The distance between the midpoints of CD and DE will be half the length of CE, so will be 12 cm.