Answer:
The mean value theorem is valid if f(x) is continuous in the interval (0,3) and differentiable in the interval (0,3), the problem is that f(x)=2−|4x−2| is not differentiable in x = 1/2 because 4*1/2 - 2 = 0 and the function |x| is not differentiable in x = 0.
f'(x) = (-4)*(4x−2)/|4x−2|
f(3) = 2−|4*3−2| = 8
f(0) = 2−|4*0−2| = 0
Replacing in f'(c) = f(3)−f(0)/(3−0)
(-4)*(4c−2)/|4c−2| = (8 - 0)/3
(-4)*(4c−2)*3/8 = |4c−2|
-3/2*4c + 3/2*2 = |4c−2|
-6c + 3 = |4c−2|
That gives us two options
-6c + 3 = 4c−2
5 = 10c
1/2 = c
or
6c - 3 = 4c−2
-1 = -2c
1/2 = c
But f'(1/2) is not defined, therefore there is no value of c such that f(3)−f(0)=f'(c)(3−0).
No area is shown. So befoe sam divided it,
the area of tge original rectangle was . . .
8 x 0 = zero .
I think it could be 40° or 130°. Im not 100% sure however because i dont know how much all the numbers add up to. It could either be 180° or 270°
Wish I could help on so sorry
Answer:
Hence, a regular polygon that has a minimum rotation of 45 degrees to carry the polygon onto itself is:
A. octagon.
Step-by-step explanation:
We know that the for a regular polygon with 'n' sides the minimum rotation that can carry the polygon onto itself is:
Here we are given the minimum angle of rotation such that polygon is transformed to itself as 45 degree.
i.e. we have:
Hence, the number of sides of a polygon are 8.
Hence, the polygon is:
A. octagon.
( Since a polygon with 8 sides is called a octagon)
