Answer:
x = 500 yd
y = 250 yd
A(max) = 125000 yd²
Step-by-step explanation:
Let´s call x the side parallel to the stream ( only one side to be fenced )
y the other side of the rectangular area
Then the perimeter of the rectangle is p = 2*x + 2* y ( but only 1 x will be fenced)
p = x + 2*y
1000 = x + 2 * y ⇒ y = (1000 - x )/ 2
And A(r) = x * y
Are as fuction of x
A(x) = x * ( 1000 - x ) / 2
A(x) = 1000*x / 2 - x² / 2
A´(x) = 500 - 2*x/2
A´(x) = 0 500 - x = 0
x = 500 yd
To find out if this value will bring function A to a maximum value we get the second derivative
C´´(x) = -1 C´´(x) < 0 then efectevly we got a maximum at x = 500
The side y = ( 1000 - x ) / 2
y = 500/ 2
y = 250 yd
A(max) = 250 * 500
A(max) = 125000 yd²
Answer
4000
900
0
7
Step-by-step explanation:
Not so sure about the answer though
Step-by-step explanation:
1. Ampltiude is 1
The period is
is the period
The phase shift is 0
2. The Ampltiude is 2
The period is 2 pi
The phase shift is 1
3. The amplitude is 3
The period is 2 pi/3
The phase shift is -2
4.The amplitude is 2/3
The period is -10pi
The phase shift is 0
5. The Ampltiude is 1
The period is -2 pi
The phase shift is pi
6. The amplitude is 1/4
The period is -4pi
The phase shift is negative 2pi/3
7. The Ampltiude is 3
The period is 4
The phase shift is 8
(2,-2)(5,7)
7-(-2)= 9
5-2= 3
9/3= 3
slope = 3
(you could also calculate the slope by just counting up how many units it goes up/down when you pick a point from the x-axis and move left/right. basically counting the rise over run)
