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Orlov [11]
2 years ago
11

I need help with this question so hard

Mathematics
1 answer:
qaws [65]2 years ago
3 0

Answer:

The answer to part B will be for length the mean is 2.08, the median is 2.6, and the mode is 2.6. For height the mean is 1.5, the median is 1.4, and there isn't a mode since no number repeat. It will the 0.6, 1.0, 1.4, 1.7, 2.8. Hope this helps!

Step-by-step explanation:

You might be interested in
What two whole numbers is 29−−√ between?: 3 and 4 4 and 5 5 and 6 6 and 7
jolli1 [7]

The two whole numbers are 5 and 6 ⇒ 3rd answer

Step-by-step explanation:

To prove that a square root number lies between which two consecutive integers do that

  • Find a square number less than the number under the root
  • Find a square number greater than the number under the root
  • Find the square root of the square numbers, they will be the two integers that the root lies between them

∵ The number is \sqrt{29}

- Find a square number less than 29

∵ 25 is a square number

∵ 25 is less than 29

- Find a square number greater than 29

∵ 36 is a square number

∵ 36 is greater than 29

∴ 25 < 29 < 36

- Take √ for each number

∴ \sqrt{25} < \sqrt{29} < \sqrt{36}

∵ \sqrt{25}  = 5

∵ \sqrt{36}  = 6

∴ 5 <  \sqrt{29}  < 6

The two whole numbers are 5 and 6

Learn more:

You can learn more about the numbers in brainly.com/question/9621364

#LearnwithBrainly

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The answer to your math problem is0.083333
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4200 and 2100 simplified to there lowest terms
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Point C,D and E are collinear on CE, and CD:DE = 3/5. C is located at (1,8), D is located (4,5), and E is located at (x,y)
Ugo [173]
Point c and d are the xy factor
7 0
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Find the perimeter of a triangle with points A(1,2), B(1,8), and C(5,5) on a Cartesian coordinate plane.
Assoli18 [71]

Check the picture below.

the distance from 1,2 to 1,8 is simply 6 units, we can read that off the grid.  Now let's see what the other distances are, and add them all up to get the perimeter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{2})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AC=\sqrt{(5-1)^2+(5-2)^2}\implies AC=\sqrt{4^2+3^2} \\\\\\ AC=\sqrt{25}\implies AC=5 \\\\[-0.35em] ~\dotfill

\bf B(\stackrel{x_1}{1}~,~\stackrel{y_1}{8})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) \\\\\\ BC=\sqrt{(5-1)^2+(5-8)^2}\implies BC=\sqrt{4^2+3^2} \\\\\\ BC=\sqrt{25}\implies BC=5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{perimeter}{6+5+5\implies 16}~\hfill

7 0
3 years ago
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