Aluminum has a density of 2.7g/cm how much space in cm 3 would 100 grams of aluminum occupy?

Sodium hydroxide is classified as a strong base in water. This means that it produces no hydroxide ions. 100% of the maximum num

mr Goodwill [35]

Answer:

Hi

Sodium Hydroxide is a strong base, it dissolves easily in water producing a large amount of calories and completely dissolving in its ions, to give hydroxide ions, as seen in the reaction:

NaOH(ac) ⇒ Na+(ac) + OH-(ac)

In the presence of ambient humidity, sodium hydroxide reacts with carbon dioxide to generate sodium carbonate. The gradual hydration generates six different hydrates: NaOH.H2O, NaOH.2H2O, NaOH.3.5H2O, NaOH.4H2O, NaOH.5H2O, NaOH.7H2O. Its great affinity for water causes a reduction in water vapor pressure and for that reason it is a very good drying agent.

Explanation:

8 0

3 years ago

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What is the pH of a buffer solution upon mixing 15.0 mL of 0.40 M HCl and 20.0 mL of 0.50 M NH? Kb (NH3) = 1.8 x 10 E. 7.00 A. 9

vladimir2022 [97]

Answer: The pH of resulting solution is 9.08

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ ........(1)

For HCl:

Molarity of HCl = 0.40 M

Volume of solution = 15.0 mL

Putting values in equation 1, we get:

$0.40M=\frac{\text{Moles of HCl}\times 1000}{15.0mL}\\\\\text{Moles of HCl}=0.006mol$

For ammonia:

Molarity of ammonia = 0.50 M

Volume of solution = 20.0 mL

Putting values in equation 1, we get:

$0.50M=\frac{\text{Moles of ammonia}\times 1000}{20.0mL}\\\\\text{Moles of ammonia}=0.01mol$

The chemical reaction for hydrochloric acid and ammonia follows the equation:

$HCl+NH_3\rightarrow NH_4Cl$

Initial: 0.006 0.01

Final: - 0.004 0.006

Volume of solution = 15.0 + 20.0 = 35.0 mL = 0.035 L (Conversion factor: 1 L = 1000 mL)

To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:

$pOH=pK_b+\log(\frac{[salt]}{[base]})$

$pOH=pK_b+\log(\frac{[NH_4Cl]}{[NH_3]})$

We are given:

$pK_b$ = negative logarithm of base dissociation constant of ammonia = $-\log (1.8\times 10^{-5})=4.74$

$[NH_4Cl]=\frac{0.006}{0.035}$

$[NH_3]=\frac{0.004}{0.035}$

pOH = ?

Putting values in above equation, we get:

$pOH=4.74+\log(\frac{0.006/0.035}{0.004/0.035})\\\\pOH=4.92$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\\pH=14-4.92=9.08$

Hence, the pH of the solution is 9.08

3 0

4 years ago

You conduct an experiment that requires the creation of an ammonia solution. You do this by reacting 50.0 L of nitrogen gas with

ozzi

Answer : The molarity of the resulting ammonia solution is, 0.89 M

Explanation :

The balanced chemical reaction is:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

First we have to calculate the moles of nitrogen gas.

As we know that at STP, 1 mole of gas occupies 22.4 L volume of gas.

As, 22.4 L volume of nitrogen gas present in 1 moles of nitrogen gas

So, 50.0 L volume of nitrogen gas present in $\frac{50.0}{22.4}=2.23$ moles of nitrogen gas

Thus, the moles of nitrogen gas is 2.23 moles.

Now we have to calculate the moles of ammonia gas.

From the reaction, we conclude that

As, 1 mole of $N_2$ react to give 2 mole of $NH_3$

So, 2.23 moles of $N_2$ react to give $2.23\times 2=4.46$ moles of $NH_3$

Now we have to calculate the molarity of the resulting ammonia solution.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of ammonia}}{\text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{4.46mole}{5.0L}$

$\text{Molarity}=0.89M$

Therefore, the molarity of the resulting ammonia solution is, 0.89 M

7 0

3 years ago

In nuclear fusion what occur ?

Murljashka [212]

Answer) 1

Lighter elements are converted to the higher elements. They fuse together to become one big nucleus. Just as two small drops can fuse to become a bigger one.

4 0

4 years ago

What hypothesis can you draw about penicillin

astra-53 [7]

Penicillin V is an antibiotic in the penicillin group of drugs. It fights bacteria in your body. Penicillin V is used to treat many different types of infections caused by bacteria, such as ear infections,. Penicillin V may also be used for other purposes not listed in this medication guide.

7 0

4 years ago