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hammer [34]
1 year ago
9

(a) What is the maximum number of unpaired electrons in a lanthanide ion?

Chemistry
2 answers:
Ronch [10]1 year ago
8 0

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PtichkaEL [24]1 year ago
7 0

Gd^{3+}  is the maximum number of unpaired electrons in a lanthanide ion.

<h3>What is meant by unpaired electrons?</h3>

Valence electrons are merely those that are in an atom's outermost shell, whereas unpaired electrons are electrons in an orbital that are alone. For instance, the electrical configuration of an atom is 1s2,2s2,2p6,3s1. An electron that is not paired has a magnetic dipole moment, however an electron pair does not since the two electrons' magnetic dipole fields cancel out because they have different spins. As a result, an atom with unpaired electrons behaves like a magnetic dipole and engages in magnetic field interaction.

A valence electron pair that does not share or form a bond with another atom is known as a lone pair. Lone pairs are a subset of the valence electrons in a molecule and are located at the outermost electron shell of an atom. The electrons that are not paired are known as unpaired electrons.

Hence Gd^{3+} is the maximum number of unpaired electrons in a lanthanide ion.

To learn more about unpaired electrons refer to:

brainly.com/question/19480525

#SPJ4

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<u>Explanation:</u>

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We are given:

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Calculating the mass contributed by the nucleus = m_{He}-2(m_e)

Mass of the nucleus of He-4 atom = 6.64648\times 10^{-24}-(2\times (9.10939\times 10^{-28}))=(6.64648-0.0018219)\times 10^{-24}=6.64466\times 10^{-24}

To calculate the fraction of atom's mass contributed by the nucleus, we use the equation:

\text{Fraction of atom's mass contributed by nucleus}=\frac{\text{Mass of nucleus}}{\text{Mass of atom}}

Putting values in above equation, we get:

\text{Fraction of atom's mass contributed by nucleus}=\frac{6.64466\times 10^{-24}g}{6.64648\times 10^{-24}g}=0.99

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