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hammer [34]
2 years ago
9

(a) What is the maximum number of unpaired electrons in a lanthanide ion?

Chemistry
2 answers:
Ronch [10]2 years ago
8 0

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PtichkaEL [24]2 years ago
7 0

Gd^{3+}  is the maximum number of unpaired electrons in a lanthanide ion.

<h3>What is meant by unpaired electrons?</h3>

Valence electrons are merely those that are in an atom's outermost shell, whereas unpaired electrons are electrons in an orbital that are alone. For instance, the electrical configuration of an atom is 1s2,2s2,2p6,3s1. An electron that is not paired has a magnetic dipole moment, however an electron pair does not since the two electrons' magnetic dipole fields cancel out because they have different spins. As a result, an atom with unpaired electrons behaves like a magnetic dipole and engages in magnetic field interaction.

A valence electron pair that does not share or form a bond with another atom is known as a lone pair. Lone pairs are a subset of the valence electrons in a molecule and are located at the outermost electron shell of an atom. The electrons that are not paired are known as unpaired electrons.

Hence Gd^{3+} is the maximum number of unpaired electrons in a lanthanide ion.

To learn more about unpaired electrons refer to:

brainly.com/question/19480525

#SPJ4

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If the balloon had a volume of 3 L at a depth of 50 m, the original volume of the balloon will be

<h3 /><h3>What is Significant figures ?</h3>

Significant figures are the number of digits in a value, often a measurement, that contribute to the degree of accuracy of the value.

The pressure at a depth of 40 m is the hydrostatic pressure of the water plus the atmospheric pressure.

The hydrostatic pressure P of a liquid is given by the formula ;

P = ρgh

where,

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Total Pressure at 50 m is ;

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P₁V₁ = P₂V₂

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According to the question ;

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