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grigory [225]
3 years ago
13

the difference between the squares of two numbers is 32. twice the square of the first number increased by the square of the sec

ond number is 76. find the numbers.​
Mathematics
1 answer:
melamori03 [73]3 years ago
7 0

Answer:

The numbers are 6 and 2

6 squared = 36

2 squared = 4

So 36-4 = 32

And 36 x 2 = 72 + 4 = 76

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3(r+2)+5(2-r) =-32 can someone tell em the answer to that please
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Answer:

r = 24

Step-by-step explanation:

3(r+2)+5(2−r)=−32

Step 1: Simplify both sides of the equation.

3(r+2)+5(2−r)=−32

(3)(r)+(3)(2)+(5)(2)+(5)(−r)=−32(Distribute)

3r+6+10+−5r=−32

(3r+−5r)+(6+10)=−32(Combine Like Terms)

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−2r+16=−32

Step 2: Subtract 16 from both sides.

−2r+16−16=−32−16

−2r=−48

Step 3: Divide both sides by -2.

−2r/-2 = -48/-2

r = 24  

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