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tigry1 [53]
3 years ago
5

1

Mathematics
1 answer:
fredd [130]3 years ago
6 0
Hi there I know the answer but it was confusing so it has to be D or B
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Sally divided her 48 spools of thread evenly into six boxes. How many spools of thread did she put into each box?
lidiya [134]

Answer:

8 spools

Step-by-step explanation:

48 divided by 6

8 0
3 years ago
Read 2 more answers
Which of the following represents the correct calculation of the sampling interval?
Goshia [24]

Answer:

The correct answer is

d. Sampling Interval = Population size ÷ Sample size.

Step-by-step explanation:

According to Johnstone et al., (2014) "<em>Once the auditor has determined the appropriate sample size, a sampling interval is calculated by dividing the population size by the sample size.</em>"

Thus,

Sampling Interval = Population size ÷ Sample size.

Johnstone, K., Rittenberg, L. and Gramling, A. (2014). <em>Auditing: A Risk-Based Approach to Conducting a Quality Audit.</em> Ninth Edition.

4 0
3 years ago
What is the value of the ratio of the surface area to the volume of the cylinder?
Stella [2.4K]

Answer:

Cylinder Surface Area = (2 • π • r²) + (2 • π • r • height)

Surface Area = (2 * PI * 7^2) + (2*PI*7*22)

Surface Area = 307.8760800518 + 967.6105373057

Surface Area = 1,275.4866173575 Square Inches

Cylinder Volume   =   π • r² • height

Volume = PI * 7^2 * 22

Volume = 3,386.6368805698 Cubic Inches

Surface Area to Volume = 1,275.4866173575 / 3,386.6368805698 =

0.3766233766

Answer is A

Source: https://www.1728.org/diam.htm

Step-by-step explanation:

5 0
3 years ago
If 2^n + 1 is an odd prime for some integer n, prove that n is a power of 2. (H
vovikov84 [41]

Step-by-step explanation:

We will prove by contradiction. Assume that 2^n + 1 is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that p\mid n. Then, for some integer k\geq 1,

n=p\times k.

Therefore

  1. 2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p.

Here we will use the formula for the sum of odd powers, which states that, for a,b\in \mathbb{R} and an odd positive number n,

a^n+b^n=(a+b)(a^{n-1}-a^{n-2}b+a^{n-3}b^2-...+b^{n-1})

Applying this formula in 1) we obtain that

2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p=(2^k+1)(2^{k(p-1)}-2^{k(p-2)}+...-2^{k}+1).

Then, as 2^k+1>1 we have that 2^n+1 is not a prime number, which is a contradiction.

In conclusion, if 2^n+1 is an odd prime, then n must be a power of 2.

4 0
3 years ago
What fraction of a pound is each ingredient meat 0.35, vegetables 0.15, sauce 0.05, bread 0.05
alexira [117]
Meat =35/100
vegetables =15/100
sauce =5/100
bread =5/100
6 0
3 years ago
Read 2 more answers
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