Answer:
I think the working is actually unnecessary because of (x-c)=0 and if x is 5 (5-c)=0 c would be 5
Multiply both sides of the equation by 28 4y+7=10
Then move constants to the right side and change its sign 4y=10-7
Now subtract the numbers 4y=3 divide both sides by 4 so your answer is y=3/4
A. There is one solution. The solution is where the lines intersect. Because both are linear and do not have the same slope, they will only cross once.
B. The solution is (3,4) since this is the coordinate at which the two lines intersect.
Answer:
Either x≈ -1.12 or x ≈0.45
Step-by-step explanation:
Using the quadratic formula to solve this, we will follow the steps below;
First, write down the quadratic formula;
x = -b ±√b² - 4ac /2a
From the question, the equation given is: 6x²+4x−3=0
comparing the equation given withe standard equation ax² + bx + c=0
a= 6 b= 4 and c = -3
We can now proceed to insert the values into the formula;
x = -4 ±√4² - 4(6)(-3) /2(6)
x = -4 ±√16+72 /12
x = -4 ±√88 /12
Either x = -4+√88 /12
x ≈0.45
OR
x = -4 -√88 /12
x≈ -1.12
Either x≈ -1.12 or x ≈0.45
Answer:
16
Step-by-step explanation:
the answer is 16 I think
