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Olin [163]
3 years ago
14

Create an equivalent system of equations using the sum of the system and the first equation.

Mathematics
2 answers:
lakkis [162]3 years ago
8 0

Answer: 829393

Bn

Step-by-step explanation:

Andrei [34K]3 years ago
8 0

Answer:

−5x + 4y = 8

−x + 5y = 10

Step-by-step explanation:

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Match the equation with the step needed to solve it.
Harman [31]
1 subtract 1 2m - 1 = 3m 
<span>2 subtract 2 2m = 1 + m </span>
<span>3 subtract m m - 1 = 2 </span>
<span>4 add  2 + m = 3 </span>
<span>5 subtract 2m -2 + m = 1 </span>
<span>6 add 1 3 = 1 + m 
1.5.
2.4
3.1
42
56
63</span>
3 0
3 years ago
The value of b when solving the equation 2 (6 + 12) = 16 is:
elena-s [515]

Answer:

Step-by-step explanation:

2(6+12)=16

2 X 6 +  2  X  12

12     +     24

       26  =  16

HOPE U GE5T IT

8 0
3 years ago
5y - 4x = -7<br> 2y + 4z = 14<br> Solve for x and y
castortr0y [4]

Answer:

et's solve for x.

5y−4x=−72y+4z

Step 1: Add -5y to both sides.

−4x+5y+−5y=−72y+4z+−5y

−4x=−77y+4z

Step 2: Divide both sides by -4.

−4x

−4

=

−77y+4z

−4

x=

77

4

y−z

Answer:

x=

77

4

y−z

Let's solve for y.

5y−4x=−72y+4z

Step 1: Add 72y to both sides.

−4x+5y+72y=−72y+4z+72y

−4x+77y=4z

Step 2: Add 4x to both sides.

−4x+77y+4x=4z+4x

77y=4x+4z

Step 3: Divide both sides by 77.

77y

77

=

4x+4z

77

y=

4

77

x+

4

77

z

Answer:

y=

4

77

x+

4

77

z

Step-by-step explanation:

I think that can help :) wanna chat add me as  friend

8 0
3 years ago
Read 2 more answers
Hi please can you help me this is a new topic and I’m very confused
olchik [2.2K]

Answer: the large jar is cheaper

Step-by-step explanation:

If you divide the £1.54 by 440g and £1.26 by 340g, you'll find which one is cheaper per gram :

1.54/440 = 0.0035

1.26/340 = 0.0037

So, by comparing both prices/gram, you've found that the large jar is cheaper.

8 0
2 years ago
If z^2+1/z^2=11 , find the value of z^3-1/z^3,using only the positive value of z-1/z
vredina [299]
Hello,

Let's assume

t=z- \dfrac{1}{z} \\\\&#10;&#10;t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\&#10;&#10;t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\&#10;=z^3 - \dfrac{1}{z^3} -3(z-\dfrac{1}{z})\\\\&#10;z^3 - \dfrac{1}{z^3}=t^3+3t=3^3+9=27+9=36&#10;&#10;&#10;
7 0
3 years ago
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