Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:

Likewise:

Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

Likewise:

Since ∠QAC ≅ ∠PAB:

And by substitution:

Thus:

Then by SAS Congruence:

And by CPCTC:

4w +8. C.
It’s 4 * width for perimeter and two of the sides are longer by 4in so 2*4=8
All the points if they lay on top of eachother
if they arent on top of eachother, they can intersect at 2 points
23 and 1/4 or 93/4 explanation: 2.5 x 3 for 1 mile u get 7.5 then multiply by 3.1
X intercepts = (6/7, 0)
y intercept = (0,-6)