Question

HELP ITS OVERDUEEE PLEASE PLEASE PLEASE ILL LOVE YOU FOREVER. Suppose that a movie is being filmed. An action shot requires an object to be thrown upward with an initial velocity of 48 feet per second off the top of the plaza, a height of 640 feet. The height h(t) in feet of the object after t seconds is given by the function h(t) = – 16t2 + 48t + 640. Determine how long before the object strikes the ground. (Hint: Let the height,
h(t), be 0 and solve for t.)

Answer 1

Answer:

the height of the object is  and the height at 6 seconds is .

b. the height of the object increases and then decreases.

c. -16(t - 9) (t +4)

i really really really hope this helps