answer
(x+7)^2 + (y-4)^2 = 64
set up equation
the equation of a circle is (x - h)^2 + (y - k)^2 = r^2
where h is the center x coordinate and k is the center y coordinate
values
from the point (-7,4) we know that h = -7 and k = 4
since the radius is 8, r^2 = 8^2 = 64
plug in values
now that we have all the values, we plug them into (x - h)^2 + (y - k)^2 = r^2
(x - h)^2 + (y - k)^2 = r^2
(x - (-7))^2 + (y-4)^2 = 64
(x+7)^2 + (y-4)^2 = 64
The center is at origin O(0,0).
If it contains the point, P(-8,6), then the radius r is, by Pythagoras theorem,
r=sqrt((-8)^2+6^2)=10
The general equation of a circle at centre (xc,yc) with radius r is given by
(x-xc)^2+(y-yc)^2=r^2
Substituting r=10, (xc,yc)=(0,0)
the resulting equation is therefore
(x-0)^2+(y-0)^2=10^2
or simply
x^2+y^2=100
Answer: Yes it is!
Step-by-step explanation:
Step-by-step explanation:
is they're any pictures that go with these?
Answer:
i'm not sure if i'm right but think is cube
