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Murrr4er [49]
2 years ago
7

Select all of the ordered pairs that are solutions to the system

Mathematics
1 answer:
Gwar [14]2 years ago
6 0

Answer:

ALL of them

Step-by-step explanation:

They are all inside or on the border of the graphing solution

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The surface area of this rectangular prism is 34 square centimeters. What is the volume is the width is 1 cm, the length is 2 cm
Bezzdna [24]

Answer: 10\ cm^3

Step-by-step explanation:

Given

The surface area of a rectangular prism is 34\ cm^2

Width of prism w=1\ cm

Length of prism l=2\ cm

height of prism h=x\ cm

Surface area is given by

S.A.=2[lw+wh+hl]

Put values

34=2[2\times 1+1\times x+2x]\\17=2+3x\\15=3x\\x=5\ cm

Now, the volume of Prism is given by

V=l\times w\times h

\Rightarrow V=2\times1\times 5=10\ cm^3

8 0
2 years ago
Shannon wants to buy cupcakes for her friend's birthday party. The bakery she goes to sells cupcakes for $3.50 each. The bakery
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So I think it would be $35 because if you multiply $3.50 by ten then it would be $35
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3 years ago
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the measure of the angle triangle are in the ratio 2:3:4. in degrees; what is the measure of the largest angle of the triangle
emmasim [6.3K]
The answer is 80, 2x+3x+4x=180, so x=20. 20*4=80.
4 0
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In the unit circle, the length of arc intercepted by an angle equals the radian measure of this angle. True False
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True. would be the righh answer
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3 years ago
How many "words" can be written using exactly five A's and no more than three B's (and no other letters)?
kakasveta [241]

This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.

Case 1: Five A's and One B

Total number of letters = 6

Total number of words possible = \frac{6!}{5!*1!}=6

Case 2: Five A's and Two B's

Total number of letters = 7

Total number of words possible = \frac{7!}{5!*2!}=21

Case 3: Five A's and Three B's

Total number of letters = 8

Total number of words possible = \frac{8!}{5!*3!}=56

Total number of possible words will be the sum of all three cases.

Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83

8 0
3 years ago
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