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Pavlova-9 [17]
3 years ago
12

Examine the right triangle. What is the length of the hypotenuse, c? Answers are in the pic

Mathematics
2 answers:
Olenka [21]3 years ago
7 0

a^2+b^2=c^2 <----- the equation to find out sides for a right triangle

stepan [7]3 years ago
5 0

Every right triangle follows the pythagorean theorem: given the legs a and b and the hypothenuse c we have

a^2+b^2=c^2 \implies c=\sqrt{a^2+b^2}

In your case, a=3 and b=5, so we have

c=\sqrt{3^2+5^2}=\sqrt{9+25}=\sqrt{34}

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Find the area of the figure. Use 3.14 as π.
Karolina [17]

Answer: D. 94.25 in²

Step-by-step explanation:

To find the total area, we will break the shape up into two different parts.

[] The rounded part is 39.25 in². Let us assume the rounded part is exactly half of a circle.

      Area of a circle:

A = πr²

      Use 3.14 for pi:

A = (3.14)r²

      Find the radius:

d / 2 = r, 10 / 2 = 5 in

      Subsittue:

A = (3.14)(5)²

A = 78.5 in²

      Divide by 2 since it is only half:

78.5 in² / 2 = 39.25 in²

[] The triangle is 55 in².

      Area of a triangle:

A = b*h/2

A = 11 * 10 / 2

A = 110 / 2

A = 55 in²

[] Total area. We will add the two parts together.

55 in² + 39.25 in² = 94.25 in²

7 0
2 years ago
Read 2 more answers
From the set (76, 77, 78), use substitution to determine which value of x makes the equation true
jeyben [28]

Answer:

The answer is C.

Step-by-step explanation:

Multiply 4 by 76, 77, and 78.

4 * 76 = 304

4 * 77 = 308

4 * 78 = 312

304 = 304, so C is the correct answer.

Hope this helps!

7 0
3 years ago
T = an + b ( solve for b )
Butoxors [25]
B=t-am is the correct answer:)
6 0
3 years ago
Evaluate the function at the given values<br> F(y) = 4y^4 - 6y^2 + 8y - 15<br> At y = 2
otez555 [7]
F(2)= 4(16) - 6(4) + 8(2) - 15
F(2)= 64 -24 + 16 - 15
F(2)= 41
7 0
3 years ago
How are percent transmittance and absorbance related algebraically?
statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:  


A ∝ b · c

As Transmittance, T =\dfrac{P}{P_0}

% Transmittance, \%T=100\times T

Absorbance,

A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T

Hence, A=\log_{10}\times \dfrac{1}{T} is the algebraic relation between absorbance and transmittance.


8 0
3 years ago
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