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Luba_88 [7]
3 years ago
9

The net of a pyramid is shown below: The net of a square based pyramid, with bases labeled 7 inches and the height of the triang

le labeled 14 inches. The surface area of the solid is square inches. (3 points)

Mathematics
2 answers:
ddd [48]3 years ago
7 0

Answer:

  • 245 in²

Step-by-step explanation:

The surface area is the sum of the areas of square base and triangle sides

  • S = 7² + 4*(1/2*7*14) =
  • 49 + 196 =
  • 245 in²
tester [92]3 years ago
6 0

Answer:

7 x 14 x 4 = 392

Step-by-step explanation:

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Which of the following shows the extraneous solution to the logarithmic equation below???
avanturin [10]
Short Answer x = - 6
Remark
You gave the second best answer. 

The trick here is not to divide both sides by 2. Solve the problem this way.

log_5(x + 1)^2 = 2 Take the antilog of both sides
(x + 1)^2 = 5^2       Expand the equation
x^2 + 2x + 1 = 25   Subtract 25 from both sides.
x^2 + 2x - 24 = 0    Factor
(x + 6)(x - 4) = 0     Find the zeros.

x + 6 = 0
x = - 6  <<<<<<<< Answer. This is the extraneous root.
The reason this is an extraneous root is that x<=0 do not have a logarithem

x - 4 = 0
x = 4    This is a legitimate result to the original equation.
7 0
3 years ago
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Someone help plz ASAP this is hard
Anna007 [38]

Answer:

The first answer.

Step-by-step explanation:

4 0
3 years ago
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How many terms are in the arithmetic sequence 7, 1, −5, …, −161?
uranmaximum [27]

Answer:

29

Step-by-step explanation:

The n th term of an arithmetic sequence is

• a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

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7 - 6n + 6 = - 161

13 - 6n = - 161 ( subtract 13 from both sides )

- 6n = - 174 ( divide both sides by - 6 )

n = 29

There are 29 terms in the sequence

5 0
3 years ago
The School Spirit Club is making beaded friendship bracelets with the school colors to sell in the school store. The bracelets a
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Step-by-step explanation:

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igor_vitrenko [27]
<h2>Answer with explanation:</h2><h2></h2><h3>The confidence interval for population proportion is given by :_</h3>

p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

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