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Oksi-84 [34.3K]
3 years ago
12

Please help me with this!!!

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0
1) 4/5 + 4/5 = 1 3/5
2) 4/5 + 2/5 + 2/5 = 1 3/5
jonny [76]3 years ago
7 0

Answer-

4/5 + 4/5

4/5 + 1/5 + 3/5

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Help please it is math
Rasek [7]
B is incorrect. I may be using the wrong word, but addition and multiplication are commutative, so the numbers can be added in any order or multiplied in any order and you’d still get the same sum or product. However, you can’t do this with subtraction or division as the difference or quotient will be different.
5 0
3 years ago
A dataset consists of the composition of 77 breakfast cereals. For each cereal, the number of calories/serving and the grams of
kirza4 [7]

Answer:

50 grams of fat

Step-by-step explanation:

The equation of the line generated by the regression is  

Calories = 110 + 10 (grams of fat), where grams of fat is a variable.  

Since the value of the grams of fat is multiplied by 10, if the two cereals differ by 5 grams of fat per serving, then the caloric content per serving will differ by:

10 x 5 = 50 grams of fat

6 0
3 years ago
Which of the following is not the same as 5.63 grams? A) 0.563 hg B) 5,630 mg C) 0.00563 hg
Alex787 [66]
<span>B) 5,630
hope it helps
</span>
6 0
3 years ago
5. Find the first, fourth, and tenth terms of the arithmetic
Lubov Fominskaja [6]

The first, fourth and tenth terms of the arithmetic sequence is -6, -\frac{27}{5} and -\frac{21}{5}

Explanation:

The given rule for the arithmetic sequence is A(n)=-6+(n-1)(\frac{1}{5} )

We need to determine the first, fourth and tenth terms of the sequence.

To find the first, fourth and tenth terms, let us substitute n=1,4,10 in the general rule for the arithmetic sequence.

To find the first term, substitute n=1 in A(n)=-6+(n-1)(\frac{1}{5} ) , we get,

A(1)=-6+(1-1)(\frac{1}{5} )

A(1)=-6+(0)(\frac{1}{5} )

A(1)=-6

Thus, the first term of the arithmetic sequence is -6.

To find the fourth term, substitute n=4 in A(n)=-6+(n-1)(\frac{1}{5} ) , we get,

A(2)=-6+(4-1)(\frac{1}{5} )

A(2)=-6+(3)(\frac{1}{5} )

A(2)=\frac{-30+3}{5}

A(2)=\frac{-27}{5}

Thus, the fourth term of the arithmetic sequence is -\frac{27}{5}

To find the tenth term, substitute n=10 in A(n)=-6+(n-1)(\frac{1}{5} ) , we get,

A(10)=-6+(10-1)(\frac{1}{5} )

A(10)=-6+(9)(\frac{1}{5} )

A(10)=-6+\frac{9}{5}

A(10)=-\frac{21}{5}

Thus, the tenth term of the arithmetic sequence is -\frac{21}{5}

Hence, the first, fourth and tenth terms of the arithmetic sequence is -6, -\frac{27}{5} and -\frac{21}{5}

3 0
3 years ago
One February day in Millington, The temperatures ranged from -2°C to 7°C. What was the difference between the high and low tempe
brilliants [131]

The answer to the question is 9°C

4 0
3 years ago
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