Answer:
<em>a ) y = 2,</em>
<em>b ) x = 5,</em>
<em>c ) x = - 3,</em>
<em>d ) y = 4</em>
Step-by-step explanation:
a )
b )

c )

d )

<em>Hope that helps!</em>
Answer: I need you to zoom in more on the paper.
The paper looks blurry and fuzzy to me.
Step-by-step explanation:
A linear pair of angles has a common side, and the vertex is on the line designated by the points denoting the non-common sides.
Consider the first choice:
... the common sided is RL, and the other two points are P and M. Point R (the vertex of the angles) is not on line PM. (In fact, line PM is not shown on the diagram.)
In the second choice, the given angles do not have a common side. (They are actually "vertical" angles.)
In the 3rd choice, the common side is RN, and vertex point R is found on line MO. These angles <em>are</em> a linear pair:
... - MRN and NRO
Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form
or 
Part 1) y varies inversely with x. If y = 8 and k (the constant of variation) = 19, what is x?
we know that

substitute the given values and solve for x



Part 2) y varies inversely with x, and k (the constant of variation) = 23. What is the value of y when x = 7?
we know that

substitute the given values and solve for y



Part 3) y varies inversely with x. When y = 6.7, x = 1. What is the value of k, the constant of inverse variation?
we know that

substitute the given values and solve for k


6x² - x -12. This is a quadratic equation. Find its roots (Zeros):
x' = [-b+√(b²-4.a.c)]/2a and x" = [-b-√(b²-4.a.c)]/2a
x' = 3/2 and x" = - 4/3
remember : ax²+bx + c = a(x-x')(x-x')
Then 6x² -x - 12 = 6(x-3/2)(x+4/3) (Reduce to the same denominator and simplify after reduction):
(2x-3)(3x+4)