Write 17 as a decimal. ---- 20
1 answer:
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So with this, I will be using the substitution method. With the first equation, substitute (y+3) into the x variable and solve for y:
Next, now that we have the value of y, substitute it into either equation to solve for x:
<u>And this is how you get your final answer (5,2).</u>
Answer:
About $241.11
Step-by-step explanation:
So, Karen receives 18.2 cents per paper.
She delivers 124 paper per day.
In other words, on days other than Sunday, she will make a total of:
On Sunday, each paper is sold for $0.70 or 70 cents. She also sells 151 Sunday papers. Thus, on a Sunday, she will make a total of:
Therefore, in one week, she will do the first equation six times and the Sunday equation once. Thus, her total pay will be:
Answer:
We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.
Step-by-step explanation:
We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.
Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.
Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.
- Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
- Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
- Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
- Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).
So, the number of passwords with 4 different digits we can write = = 360 possibilities.
Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.