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Serggg [28]
3 years ago
7

How does a circuit breaker protect a refrigerator?

Physics
1 answer:
kodGreya [7K]3 years ago
5 0

Answer:

When the circuit breaker trips and turns off, it can shut off power to the appliance. This not only protects your home from damage, but it also protects the appliance itself.

Explanation:

What is a circuit breaker. A circuit breaker is an electrical switch designed to protect an electrical circuit from damage caused by overcurrent/overload or short circuit. Its basic function is to interrupt current flow after protective relays detect a fault.

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Please help me with physical science!
natta225 [31]

the first one is A and the second one is B and the third one is D

7 0
4 years ago
A bus with a vertical wind shield moves horizontally
Katena32 [7]

Answer:

(3) 53°

Explanation:

We want to measure the angle that the rains form with the vertical wind shield, so we have to measure the angle relative to the vertical. This means that we can write the following equation

tan \theta = \frac{v_x}{v_y}

where

v_y = 30 km/h is the speed of the rain, which travels vertically

v_x = 40 km/h is the speed of the bus, which travels horizontally

Substituting, we find

\theta=tan^{-1}(\frac{40}{30})=53^{\circ}

8 0
3 years ago
A 50-ω resistor is connected to a 9.0 V battery. How much thermal energy is produced in 7.5 minutes?
Aleksandr-060686 [28]

Answer:

1.2 102j

Explanation:

because it is the most important for me

3 0
3 years ago
How to do this question
Yuki888 [10]

Answer:

64°

Explanation:

The triangle is an isosceles triangles (both legs are equal to the radius of the circle), so that means the base angles are the same.

Angles of a triangle add up to 180°, so:

128 + 2x = 180

2x = 52

x = 26

∠1 is complementary to the base angle, so:

∠1 = 90 − 26

∠1 = 64

7 0
3 years ago
A proton is moved from the negative to the positive plate of a parallel-plate arrangement. The plates are 1.50 cm apart, and the
Nana76 [90]

(a) The proton’s potential energy change is 3.6 x 10⁻¹⁸ J.

(b) The potential difference between the negative plate and a point midway between the plates is 11.25 V.

(c) The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.

<h3>Potential energy of the proton</h3>

U = qΔV

where;

  • q is charge of the proton
  • ΔV is potential difference

U = q(Ed)

U = (1.6 x 10⁻¹⁹)(1500 x 1.5 x 10⁻²)

U = 3.6 x 10⁻¹⁸ J

<h3>Potential difference between the negative plate and a point midway</h3>

ΔV = E(0.5d)

ΔV = 0.5Ed

ΔV = 0.5 (1500)(1.5 x 10⁻²)

ΔV = 11.25 V

<h3>Speed of the proton </h3>

U = ¹/₂mv²

U = mv²

v² = 2U/m

where;

  • m is mass of proton = 1.67 x 10⁻²⁷ kg

v² = (2 x 3.6 x 10⁻¹⁸) / ( 1.67 x 10⁻²⁷)

v² = 4.311 x 10⁹

v = √(4.311 x 10⁹)

v = 6.57 x 10⁴ m/s

Thus, the proton’s potential energy change is 3.6 x 10⁻¹⁸ J.

The potential difference between the negative plate and a point midway between the plates is 11.25 V.

The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.

Learn more about potential difference here: brainly.com/question/24142403

#SPJ1

4 0
2 years ago
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