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3 years ago

A 50-ω resistor is connected to a 9.0 V battery. How much thermal energy is produced in 7.5 minutes?

Physics

1 answer:

Aleksandr-060686 [28]3 years ago

3 0

Answer:

1.2 102j

Explanation:

because it is the most important for me

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A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction

Korvikt [17]

Answer:

The magnitude of the impulse delivered to the baseball is 7.0 Ns

Explanation:

Given;

mass of the foul ball, m = 0.14 kg

initial velocity, u = 40 m/s

final velocity, v = 30 m/s in perpendicular direction

Impulse is given as change in momentum;

initial momentum in horizontal direction, Pi = mu

Pi = 0.14 x 40 = 5.6 Ns

final momentum in perpendicular direction, Pf = mv

Pf = 0.14 x 30

Pf = 4.2 Ns

The resultant impulse is given by;

J² = 5.6² + 4.2²

J² = 49

J = √49

J = 7.0 Ns

Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns

5 0

3 years ago

What is the second cooler layer of ocean water?

maw [93]

The surface zone :)))))))))

8 0

4 years ago

The block has a weight of 75 lblb and rests on the floor for which μkμk = 0.4. The motor draws in the cable at a constant rate o

WINSTONCH [101]

The given question is incomplete. The complete question is as follows.

The block has a weight of 75 lb and rests on the floor for which $\mu k$ = 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.

Determine the output of the motor at the instant $\theta = 30^{o}$ .

Explanation:

We will consider that equilibrium condition in vertical direction is as follows.

$\sum F_{y} = 0$

N - W = 0

N = W

or, N = 75 lb

Again, equilibrium condition in the vertical direction is as follows.

$\sum F_{x} = 0$

$T_{2} - F_{k}$ = 0

$T_{2} = \mu_{k} N$

= $0.4 \times 75 lb$

= 30 lb

Now, the equilibrium equation in the horizontal direction is as follows.

$\sum F_{x} = 0$

$T Cos (30^{o}) + T Cos (30^{o}) = T_{2}$

$2T Cos (30^{o}) = T_{2}$

or, T = $\frac{T_{2}}{2 Cos (30^{o})}$

= $\frac{30}{2 Cos (30^{o})}$

= $\frac{30}{1.732}$

= 17.32 lb

Now, we will calculate the output power of the motor as follows.

P = Tv

= $17.32 lb \times 6$

= $103.92 \times \frac{1}{550} \times \frac{hp}{ft/s}$

= 0.189 hp

or, = 0.2 hp

Thus, we can conclude that output of the given motor is 0.2 hp.

3 0

3 years ago

Read 2 more answers

What is the shape of the trajectory that a charged particle follows in a uniform magnetic field?

Darya [45]

Answer:

circle

Explanation:

5 0

3 years ago

Exercise should challenge your body and be at a greater intensity than your usual bif daily activity. Discuss

vekshin1

Answer:

A fan pushes hot air out of a vent and into a room. The hot air displaces cold air in the room, causing the cold air to move closer to the floor.

The hot air displacing the cold air is an example of transfer by

Explanation:

4 0

4 years ago