The answer is 10
............
we know that
If the point has an nonzero abscissa (x coordinate) then it can be located in any of the four quadrants
If the point has an negative ordinate (y coordinate) then it can be located in Quadrant III or Quadrant IV
therefore
the answer is the option
Quadrant III or Quadrant IV
It may help you to consider the standard normal curve. If the mean here is 70%, then 0.5 of the area under this curve. In other words, half the students received a grade > 70%. That would be 100 students.
Note that 84 is 2 std dev above the mean.
Recall the Empirical Rule: 95% of scores lie within 2 std. dev of the mean.
Measuring from the mean, that would be 47.5% above the mean and 47.5% below the mean. The area to the right of the mean is 0.5. Subtract 0.475 from that to obtain the fraction of students who rec'd a grade greater than 2 std dev from the mean: It's 0.025.
Then the # of students who rec'd a grade greater than 84% would be
0.025(200 students) = 5 students.
I'm not sure which one of the equations you are requesting but for the pemdas one is it 11, you do the parenthesis first then add three.
Answer:
52ft²
Step-by-step explanation:
A=2(wl+hl+hw)
l= 2ft
w=3ft
h=4ft
A=2(wl+hl+hw)
= 2(3X2+ 4X2+4X3)
= 2(6+8+12)
2(26) =2X26 = 52
