A fathers age = three less than two times the son's age can be writtens as: f=2s-3. Since the difference in their age, f-s=30, we can solve for s and find that s=f-30. plugging this in to the first equation, we get f=2(f-30)-3 = 2f-60-3 =2f-63
f=2f-64
solvinh for f yields,
f=64
if thr father is 64, the son's age is therfore 64-30=34
Area=legnth times width
so if you know the area then solve for width
area=legnth times width
divide both sdies by legnth
area/legnth=width
if you have the legnth then you can solve
area divided by legnth=width
base 16y^2
height y^2 + y + 3
V = b*h
V = 16y^2(y^2 + y + 3)
V = 16y^4 + 16y^3 + 48y^2
Last option
Answer:
please what should we solve for .
Answer:
36
Step-by-step explanation:
If s is the side length, then the area of the square is
A = s^ = (6)^2 = 36
This is how you were expected to answer this question. However, the actual correct answer is 36 cm^2.
