I NEED HELP PLZ ( WILL GIVE BRAINLIST) NO LINKS

Mathematics

1 answer:

raketka [301]3 years ago

3 0

Answer:

2 1/2

Step-by-step explanation:

i used the lwh for this/ (length) (width) (height)

Branliest will be appreciated and thanks!

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Find the 52nd term of the arithmetic sequence 5, 9, 13

IRINA_888 [86]

Answer:

209

Step-by-step explanation:

You would first create an explicit formula for the provided sequence.

The basic explicit formula for arithmetic sequences is $a_{n} = d(n-1) + a_{1}$ , where an is the number of the term, d is the number you are adding or subtracting by, n the location of the term, and a1 is the first number.

We would then substitute the values given into the formula.

We are trying to solve the value of the 52nd term. This makes n = 52. The first number of the sequence is 5, so a1 is 5. Finally, d is 4 because we are adding 4 to each number in the sequence.

Therefore, our resulting equation would be $a_{n} =4(52-1)+5$ , which equals 209.

6 0

2 years ago

The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was

alekssr [168]

The formula would be set up as ratios (or fractions). The first ratio is 6:5, which in total is 11. There were 6 yes out of 11, so the fraction = 6/11.

The second fraction has a total of 5918, however you do not know the amount of yes votes, so the variable placeholder will be called "x".

The final formula would be:
6/11 = x/5918

You do cross multiplication and you get:
11x = 35508. You divide both sides, and you get x = 3228.

Because x is the placeholder for the amount of yes votes, and x = 3228, the amount of yes votes is 3228

6 0

3 years ago

Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )

Zina [86]

Answer:

$\purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ \sqrt{6} }{6} = \frac{1}{ \sqrt{6} } \\ \\ \therefore \: \sin( \alpha ) = \sqrt{1 - { \cos}^{2} ( \alpha ) } \\ \\ = \sqrt{1 - \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} } \\ \\ = \sqrt{1 - {\frac{1}{ {6} }}} \\ \\ = \sqrt{ {\frac{6 - 1}{ {6} }}} \\ \\ \red{\sin( \alpha ) = \sqrt{ { \frac{5}{ {6} }}} } \\ \\ \tan( \alpha ) = \frac{\sin( \alpha ) }{\cos( \alpha ) } = \sqrt{5} \\ \\ \sin( \beta ) = \frac{ \sqrt{2} }{4} \\ \\ \implies \: \cos( \beta ) = \sqrt{ \frac{7}{8} } \\ \\ \tan( \beta ) = \frac{\sin( \beta ) }{\cos( \beta ) } = \frac{1}{ \sqrt{7} } \\ \\ \tan( \alpha - \beta ) = \frac{ \tan \alpha - \tan \beta }{1 + \tan \alpha . \tan \beta} \\ \\ = \frac{ \sqrt{5} - \frac{1}{ \sqrt{7} } }{1 + \sqrt{5} . \frac{1}{ \sqrt{7} } } \\ \\ = \frac{ \sqrt{35} - 1 }{ \sqrt{7} + \sqrt{5} } \\ \\ \purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$