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3 years ago

I NEED HELP PLZ ( WILL GIVE BRAINLIST) NO LINKS

Mathematics

1 answer:

raketka [301]3 years ago

3 0

Answer:

2 1/2

Step-by-step explanation:

i used the lwh for this/ (length) (width) (height)

Branliest will be appreciated and thanks!

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What the answer I don’t know it

meriva

The answer is B since a negative number being subtracted cancels out and becomes a number, for example: since its -(-3) it becomes positive.

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3 years ago

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PLEASE ANSWER Which characteristic is shared by both prokaryotes and eukaryotes?

Norma-Jean [14]

Answer:

the 3rd one,

Step-by-step explanation:

Because it is the 3rd one

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3 years ago

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100 POINTS plz help Chuck drops a rock from a height of 70 m. How long will it take the rock to hit the ground?

lord [1]

Answer:

3.8

Step-by-step explanation:

We are going to plug in the values of the equation, so h(t)=-4.9^2+v0t+h0 will

now be h(t)=-4.9^2+0+70

Now we will find the a b and c of the equation, a=-4.9 b=0 c=70

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3 years ago

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Select ALL the correct answers.

Marina CMI [18]

Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

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3 years ago

Can someone help me with this

jolli1 [7]

Answer:

4 sides

Step-by-step explanation:

A lot of math is about pattern matching. Here, you're asked if sides are the same length (one side matches another), if there are right angles (square corners), and if the number of angles or sides is 4.

You might make the observations ...

pink: 2 pairs of parallel sides that are the same length (4 sides). Adjacent sides are different length.

orange: all 4 sides are congruent and at right angles

blue: 2 pairs of parallel sides that are the same length (4 sides). Adjacent sides are different length.

green: 2 pairs of parallel sides that are the same length--4 sides and 4 right angles. Adjacent sides are different length.

The only feature in common is "4 sides."

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2 years ago