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leonid [27]
3 years ago
9

Solve for x. 11x – 19x = -16 x =

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
5 0
Your answer is simple, it's x = 0
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Race Times
schepotkina [342]

Answer:

B) The median will increase.

Step-by-step explanation:

he original median was 35 and the new median is 36. The median will increase.

7 0
2 years ago
LetF(x, y) be the statement "xcan fooly," where the domain consists of all people ofthe world. Use quantifiers to express each o
Sindrei [870]

Answer:

See steps below

Step-by-step explanation:

Let F(x, y) and W be

F(x,y) = “x can fool y”

W the set of all the people in the world

a) <u>Everybody can fool Fred.</u>

\forall x \in W,F(x, Fred)

b) <u>Evelyn can fool everybody.</u>

\forall y\in W, F(Evelyn, y)

c) <u>Everybody can fool somebody.</u>

\forall x \in W,\exists y :F(x,y)

d) <u>There is no one who can fool everybody</u>.

\nexists x \in W: \forall y ,F(x,y)

e) <u>No one can fool both Fred and Jennifer.</u>

\nexists x \in W: F(x,Fred)\wedge F(x,Jennifer)

f) <u>Nancy can fool exactly two people.</u>

\exists x,y \in W:\forall z\neq x,z\neq y, F(Nancy,x)\wedge F(Nancy,y)\wedge (\neg F(Nancy,z))

6 0
3 years ago
there are 657 lights on you set. on any given day 6 of them burn out and need to be replaced . if each light cost $45 how much d
Klio2033 [76]

Answer:

1890, total cost of lights per week

Step-by-step explanation:

The lights cost 45 dollars per bulb and 6 go out per day, 45×6=270

270 is the cost to replace the bulbs of one day.

270×7=1890.  1890 is the cost for a whole weeks worth of replacing these bulbs.

6 0
3 years ago
Evaluate the function.<br><br> g(x)=10x+3<br><br> g(19.6)=
Zolol [24]

Answer:

199

Step-by-step explanation:

plug in x=19.6, then

g(19.6) = 10 * 19.6 +3= 199

7 0
2 years ago
If y=3x - 5, find the value of y when x = -1yn
kupik [55]

Answer:

y = 3x - 5 \\ x =  - y \\ substitute \:  - y \: in \: the \: place \: of \: x \\ y =  - 3y - 5 \\ y + 3y = 5 \\ 4y = 5 \\ y =  \frac{5}{4}

6 0
2 years ago
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