Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:

The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days


Solving (b); The value of E when d = 30.
Substitute 30 for d in 



<em>Hence, there are 5000kwh left after 30 days</em>
Answer:
A or 53 squared
Step-by-step explanation:
Answer:
$7075 or 7718
Step-by-step explanation:
91100-6200=84900
84900/11= 7718.18181818 or rounded= 7718
(This is if the december month doesnt count.)
84900/12=7075
(If december is included.)
When you think of slope intercept form we think of Y=mx+b
m=slope and b = intercept
So all you do is solve for Y in your given equation.
Im going to guess the equal sign because you didn't include it. I can fix the answer is I was wrong.
3y-15=6x (add 15 to both sides)
3y=6x+15 (divide by 3)
y=2x+3 (final answer)
6.) constant = 75
7.) open sentence = 6 + 22 = 28
8.) equation = 17 + b = 47
9.) solution = when x + 37 = 62, x = 25