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3 years ago

What are C-12, C-13, and C-14 called?

Chemistry

1 answer:

vivado [14]3 years ago

3 0

Answer:

Protons: C12= 12 Protons, C13=12 Protons and C14=12 Protons

#electrons= 12+0=12 electrons in all Carbon atoms Neutron: C12=0, C13= -1, C14= -2

Atomic mass of C12, C13 and C14= 12

C12, C13, and C14 are called “ISOTOPES”

Explanation:

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Need help please! Theres three parts to this that I don't understand at all

butalik [34]

Answer:

Chemical reaction B governs the process

Explanation:

The first part of the question asks to convert the mass of the calcium carbonate given to number of moles.

Mathematically;

Number of moles = mass/molar mass

Molar mass of CaCO3 = 100 g/mol

So the number of moles of CaCO3 will be 2.49/100 = 0.0249 moles

The second part of the question asks to convert the mass of carbon iv oxide to moles of carbon iv oxide

Mathematically;

That is same as ;

Number of moles = mass/molar mass

molar mass of CO2 is 44 g/mol

Number of moles of CO2 = 1.13/44 = 0.0256 moles

Now, if we compare the values of these number of moles, we can see that there are almost equal.

What this means is that the number of moles of calcium carbonate reacted is equal to the number of moles of carbon iv oxide produced.

So what we conclude here is that we have an equal mole ratio between the two compounds.

So the reaction that would be the correct answer will present equal number of moles of carbon iv oxide and calcium carbonate

Thus, we can see that reaction B is the one that governs this process as it is the only reaction out of the three options that present the two compounds with equal number of moles.

4 0

4 years ago

A titration is performed where 0.150M sodium hydroxide solution is added to a solution of KHP.

KengaRu [80]

Answer:

0.00375 moles OF KHP

Explanation:

Equation of reaction of NaOH and KHP :

KHC₈H₄ O₄(aq) + NaOH(aq) → NaKC₈H₄O₄(aq) + H₂O(l)

the reaction required 25ml

Molarity = no of mole / volume in liters

no of moles = Molarity × volume in liters

no of moles of NaOH = 0.150 × (25/1000) = 0.00375 moles

using the balanced equation above

1 mole of NaOH requires 1 mole of KHP

therefore

0.00375 mole of NaOH will require 0.00375 mole KHP.

6 0

3 years ago

How do atoms move from the ground state to the excited state?

DanielleElmas [232]

Answer:

Absorbing energy

Explanation:

If an electron is given extra energy, such as light (photons), it becomes excited and jumps to higher energy levels/orbitals.

8 0

4 years ago

Which one of the following substances has three unpaired d electrons? A) [V(H2O)6]4+ B) [Zn(NH3)4]2+ C) [Cu(NH3)4]2+D) [Ag(NH3)2

Volgvan

Answer:

The correct option is: E) [Cr(CN)₆]³⁻

Reason: In this complex, Cr is present in +3 oxidation state and the electron configuration of Cr³⁺ is [Ar] 3d³

Therefore, the number of unpaired electrons = 3

Explanation:

A) [V(H₂O)₆]⁴⁺

Central metal: Vanadium (V)

Let the oxidation state of V be x

Oxidation state of H₂O = 0

x + 6 × (0) = +4

x = +4

Ground state electron configuration: V = [Ar] 3d³4s²

Excited state electron configuration: V⁴⁺ = [Ar] 3d¹

Therefore, the number of unpaired electrons = 1

B) [Zn(NH₃)₄]²⁺

Central metal: Zinc (Zn)

Let the oxidation state of Zn be x

Oxidation state of NH₃ = 0

x + 4 × (0) = +2

x = +2

Ground state electron configuration: Zn = [Ar] 3d¹⁰4s²

Excited state electron configuration: Zn²⁺ = [Ar] 3d¹⁰

Therefore, the number of unpaired electrons = 0

C) [Cu(NH₃)₄]²⁺

Central metal: Copper (Cu)

Let the oxidation state of Cu be x

Oxidation state of NH₃ = 0

x + 4 × (0) = +2

x = +2

Ground state electron configuration: Cu = [Ar] 3d¹⁰4s¹

Excited state electron configuration: Cu²⁺ = [Ar] 3d⁹

Therefore, the number of unpaired electrons = 1

D) [Ag(NH₃)₂]⁺

Central metal: Silver (Ag)

Let the oxidation state of Ag be x

Oxidation state of NH₃ = 0

x + 2 × (0) = +1

x = +1

Ground state electron configuration: Ag = [Ar] 4d¹⁰5s¹

Excited state electron configuration: Ag⁺ = [Ar] 4d¹⁰

Therefore, the number of unpaired electrons = 0

E) [Cr(CN)₆]³⁻

Central metal: Chromium (Cr)

Let the oxidation state of Cr be x

Oxidation state of CN⁻ = -1

x + 6 × (-1) = -3

x = +3

Ground state electron configuration: Cr = [Ar] 3d⁵ 4s¹

Excited state electron configuration: Cr³⁺ = [Ar] 3d³

Therefore, the number of unpaired electrons = 3

7 0

4 years ago

What is the buddy law in science.

solong [7]

Search it up on quizlet it’s easier they have lots of answers their

5 0

4 years ago