The temperature of the countertop changes by 0.032 °C
The quantity of heat transferred to the countertop is given by
Q = CΔT where Q = quantity of heat transferred to the countertop = 5000 J = 5 kJ, C = heat capacity of the countertop = 158.5 kJ/°C and ΔT = temperature change of the countertop.
Since we require the temperature change of the countertop, we make ΔT subject of the formula.
So, ΔT = Q/C
So, substituting the values of the variables into the equation, we have
ΔT = Q/C
ΔT = 5 kJ/158.5 kJ/°C
ΔT = 0.032 °C
So, the temperature of the countertop changes by 0.032 °C
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brainly.com/question/16384350
Answer: Belongs to the group 2A
Explanation:
As you can see, the first two ionization energies are close and low, meaning that this element ionizates easily.
Not only loses easily the first electron, but the second too
To remove the third electron you requiered a huge amount of energy
Now, elements easily ionizable are the ones from group IA, group 2A and transition metals.
The last ones have mixed characteristics in matter of how many electrons you can remove from them, so they are not a family.
Now the question: group I or group II ?
The elements of group I have low ionization energies for the first electron but high energies for the second ones.
Being all that said, the unknown element belongs to the Group 2A
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