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7nadin3 [17]
4 years ago
9

Calculate the ph of a 0.059 m solution of ca(oh)2

Chemistry
1 answer:
Vlada [557]4 years ago
5 0
Hydronium conc. = 0.059

pH = - log (0.059)

pH = - (-1.22914799)

pH = 1.229 = 1.2 ... Ans
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Ca(NO3)2 wht is the mass
bogdanovich [222]

Answer:

164.088 g/mol

Explanation: hope this helps

8 0
3 years ago
Read 2 more answers
A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling
aniked [119]

<u>Answer:</u> The mass of glucose in final solution is 0.420 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}        .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated glucose solution

M_2\text{ and }V_2 are the molarity and volume of diluted glucose solution

We are given:

M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL

Putting values in above equation, we get:

0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g

Hence, the mass of glucose in final solution is 0.420 grams

3 0
4 years ago
What is the concentration in molarity of a solution that has 54.21g of calcium hydroxide dissolved in 560mL of water?
ra1l [238]
We know that Molarity = # mol/L

In the question, we are given grams - so we need to calculate the number of moles that we are dealing with. We can do this by first finding out what the molecular formula of calcium hydroxide is: Ca(OH)_{2

This means that we have 1 calcium and 2 hydroxides.

We can find the number of moles by taking the grams given divided by the molar mass of the molecule. We can find the molar mass of the molecule by taking each atomic mass of each atom (found on the periodic table) and adding them together:

Ca = 40.08g
O = 15.999g
H = 1.008g

We have 1 calcium, 2 oxygens, and 2 hydrogens. So let's add the atomic masses together:

40.08 + 2(15.999) + 2(1.008) = 74.094g

Now that we have the molar mass, we can find the number of moles due to already knowing the given amount in the question:

54.21g/74.09g = 0.73 moles of Ca(OH)_{2}

Now that we know the number of moles, we can solve for the molarity; The other part of the question gives us 560 mL of water - but this can quickly be converted to liters by moving the decimal to the left 3 places => 0.560 L

Knowing all of this information, we can plug it into the molarity equation:

Molarity = 0.73 mol/0.56 L
Molarity = 1.30

The molarity of the solution is 1.3 M.
4 0
3 years ago
what is the difference between the number of electrons in an atom of selenium and the number of electrons in an atom of aluminum
igomit [66]

Answer:

The atomic number of Selenium is 34. This means that Selenium possesses 34 electrons.

The atomic number of Aluminium is 13. This means that Aluminium has 13 electrons.

Hence, there is a difference of 21 between the number of electrons in an atom of selenium and the number of electrons in an atom of aluminium.

Selenium has 6 electrons in it's outer most shell whereas aluminium has 3 electrons in its outer most shell. As a result, aluminium will have a greater tendency to lose one of its outer most electrons to become stable.

7 0
3 years ago
How does an increase in temperature affect the equilibrium concentration of the underlined substance and K for each of the follo
Darya [45]

Explanation:

Due to the positive value of the change in temperature, this is an endothermic reaction.

Since the forward reaction is endothermic, increasing the temperature increases the equilibrium constant (k).

In an equilibrium system, the position of the equilibrium will move in a way to annul the change made to the system. An increase in temperature for an endothermic reaction would favour the reaction, leading to increase in amount of products and decrease in amount of reactants.

3 0
3 years ago
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