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Len [333]
3 years ago
15

construct a ​99% confidence interval of the population proportion using the given information. x=240 n=300

Mathematics
1 answer:
Veronika [31]3 years ago
5 0

<u>Confidence interval for population proportion is </u>

<u>sample proportion +/- confidence coefficient*standard error of p </u>

<u>Sample proportion = p = x/n = 180/300 = 0.6 </u>

<u>Confidence coefficient is the critical value of z for 95% confidence level = 1.96 </u>

<u>Standard error of p = sqrt [p*(1-p)/n] </u>

<u>= sqrt [0.6*0.4/300] </u>

<u>= 0.0283 </u>

<u>The CI is </u>

<u>0.6 +/- 1.96*0.0283 </u>

<u>0.6 +/- 0.055 </u>

<u>lower boundary is 0.6-0.055 = 0.545 </u>

<u>upper boundary is 0.6+0.055 = 0.655 </u>

<u>The CI is (0.545, 0.655)</u>

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