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Natalija [7]
3 years ago
5

Which test point holds true for the inequality 3/2-2x>1

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0

Answer:

2/3 x - 2y ≥ 1⇒ y≤ 1/3 x -1/2

(1,6) holds false for the inequality

(2,3) false

(3,2) false

(6,1) holds true for the inequality

The solution (shaded area) lies below the boundary line, which is y = 1/3 x -1/2

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Answer:

5

Step-by-step explanation:

1,2,3,4,5,6

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This is Grade 9 Mathematics so I kinda stuck here so, if somebody can help me Please sin30⁰+csc60⁰​
mamaluj [8]

\huge\mathrm{Answer࿐}

  • \sin(30)  +  \csc(60)

  • \dfrac{1}{2}  +  \dfrac{2}{ \sqrt{3} }

  • \dfrac{ \sqrt{3 } + 4 }{2 \sqrt{3} }

To remove √3 from denominator, we multiply both numerator as well as denominator with √3

  • \dfrac{ \sqrt{3 } + 4 }{2 \sqrt{3} }  \times  \dfrac{ \sqrt{3} }{ \sqrt{3} }

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6 0
3 years ago
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What is 65 miles in 2.7 gallons unit rate rounded to the nearest hundredth
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You can't convert miles into gallons those are two different units of measurement.
4 0
4 years ago
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All the sides of a hexagon become three times the original length. find the ratio of areas of the new and old hexagons.
Anastaziya [24]
To determine the ratio, we need to know the formula of the area of an hexagon in terms of the length of its sides. We cannot directly conclude that the ratio would be 3, the same as that of the ratio of the lengths of the side, since it may be that the relationship of the area and length is not equal. The area of a hexagon is calculated by the expression:

A = (3√3/2) a^2

So, we let a1 be the length of the original hexagon and a2 be the length of the new hexagon.

A2/A1 = (3√3/2) a2^2 / (3√3/2) a1^2
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Therefore, the ratio of the areas of the new and old hexagon would be 9.
7 0
3 years ago
A man notices that a tank is half full. After emptying 600 litres from the tank, that it is now one-third full. How much does th
enot [183]
One half is equal to 3/6.
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600 litres is 1/6 of the tank. Multiply by 6 to get the capacity of a full tank.

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The tank can hold 3600 litres.
6 0
4 years ago
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