Answer:
<em>Solution:</em>
(A). For the evaluation of Type A uncertainty data, a single repeatability test containing mean, standard deviation and degrees of freedom
<em>Mean </em>
= (21.0 + 20.2 + 20.7 + 21.3 + 20.5) / 5
= 20.74 psig
<em>Standard Deviation</em>
= (0.26-0.54-0.04 + 0.56-0.24)2/5 = 0
<em>Degrees of Freedom </em>
= n-1 = 5-1
<em>= 4 </em>
(B). For the evaluation of Type B uncertainty data, because the standard deviation is zero, therefore Type B will be uncertain.
(C). Average standard
=20.74 x 5
=<em>103.70 psig</em>
D) O Water - Based Is the 1000000000000000000% correct answer
Answer
1056
Explanation:
for example
A soil is to be excavated from a borrow pit which has a density of 1.75g/cc and water content of 12%. The G is 2.7 the soil is compacted to that water content of 18% and dry density of 1.65g/cc. for 1000 m3 of soil used in fill estimate
Quantity of soil to be excavated from pit in m3
Answer:
the pressure reading when connected a pressure gauge is 543.44 kPa
Explanation:
Given data
tank volume (V) = 400 L i.e 0.4 m³
temperature (T) = 25°C i.e. 25°C + 273 = 298 K
air mass (m) = 3 kg
atmospheric pressure = 98 kPa
To find out
pressure reading
Solution
we have find out pressure reading by gauge pressure
i.e. gauge pressure = absolute pressure - atmospheric pressure
first we find absolute pressure (p) by the ideal gas condition
i.e pV = mRT
p = mRT / V
p = ( 3 × 0.287 × 298 ) / 0.4
p = 641.44 kPa
so
gauge pressure = absolute pressure - atmospheric pressure
gauge pressure = 641.44 - 98
gauge pressure = 543.44 kPa
a bricklayer, a bricklayer builds houses repairs walls and chimneys etc.
