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wlad13 [49]
3 years ago
11

To be safe, the engineers making the ride want to be sure the normal force does not exceed 1.8 times each persons weight - and t

herefore adjust the frequency of revolution accordingly. What is the minimum coefficient of friction now needed?
Engineering
1 answer:
Yuri [45]3 years ago
5 0

Answer:

μ = 0.55

Explanation:

Given that

Normal weight = 1.8 x weight of person

N= 1.8 mg

We know that friction force Fr

Fr= μ N

μ=Coefficient of friction

N=Normal force

To find  μ We have to equate friction and gravity force

Fr= Wt

μ N = m g

μ  x 1.8 m g = m g

μ = 0.55

So the coefficient of friction will be 0.55.

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Which one of the following faults cause the coffee in a brewer to keep boiling after the brewing cycle is finished?
MrRa [10]

Answer:

  C.  Welded contacts on the thermostat

Explanation:

Any fault that keeps the heating element heating when it should not is a fault that will cause the symptom described. The details <em>depend on the design of the brewer</em> (not given).

"A short at the terminals" depends on what terminals are being referenced. The device on-off switch terminals are normally connected together when the brewer is turned on, so a short there may not be observable.

"Welded contacts on the thermostat" will have the observed effect if the thermostat is the primary means of ending the brewing cycle. If the thermostat of interest is an overheat protective device not normally involved in ending the brewing cycle, then that fault may not cause the observed symptom.

__

If the heating element is open-circuit, no heating will occur. A gasket leak may cause a puddle, but may have nothing to do with the end of the brewing cycle. (Loss of water can be expected to end boiling, rather than prolong it.)

8 0
4 years ago
Consider a junction that connects three pipes A, B and C. What can we say about the mass flow rates in each pipe for steady flow
Elis [28]

Answer:

The statement regarding the mass rate of flow is mathematically represented as follows \Rightarrow \rho \times Q_{3}=\rho \times Q_{1}+\rho \times Q_{2}

Explanation:

A junction of 3 pipes with indicated mass rates of flow is indicated in the attached figure

As a basic sense of intuition we know that the mass of the water that is in the pipe junction at any instant of time is conserved as the junction does not accumulate any mass.

The above statement can be mathematically written as

Mass_{Junction}=Constant\\\\\Rightarrow Mass_{in}=Mass_{out}

this is known as equation of conservation of mass / Equation of continuity.

Now we know that in a time 't' the volume that enter's the Junction 'O' is

1) From pipe 1 = V_{1}=Q_{1}\times t

1) From pipe 2 = V_{2}=Q_{2}\times t

Mass leaving the junction 'O' in the same time equals

From pipe 3 = V_{3}=Q_{3}\times t

From the basic relation of density, volume and mass we have

\rho =\frac{mass}{Volume}

Using the above relations in our basic equation of continuity we obtain

\rho \times V_{3}=\rho \times V_{1}+\rho \times V_{2}\\\\Q_{3}\times t=Q_{1}\times t+Q_{2}\times t\\\\\Rightarrow Q_{3}=Q_{1}+Q_{2}

Thus the mass flow rate equation becomes \Rightarrow \rho \times Q_{3}=\rho \times Q_{1}+\rho \times Q_{2}

6 0
4 years ago
EnQueue(X): Thêm phần tử X vào Queue
irina [24]
Yes that is right no matter what you are talking about I’m not sure tho
6 0
3 years ago
What are the benefits of using the engineering design process? combining scientific knowledge and creativity in a rigid and stru
Trava [24]

Answer:

combining scientific knowledge, careful reasoning, and artistic invention in a flexible approach to problem-solving

Explanation:

7 0
3 years ago
What gage pressure does a skin diver experience when they dive to 35 ft in the ocean with a water temperature of 55 °F? Report y
TEA [102]

Answer:

p=15.097lbf/in^2

Explanation:

the manometric pressure is that in which the atmospheric pressure is not taken into account, so for this case only the pressure exerted by the water on the bus is calculated using the following equation.

P=ρgh

where

ρ=density of water at 55°F=999.4kg/m^3

g=9.81m/s^2

h=35ft=10.668m

Solving

P=(994.4)(9.81)(10.668)=104067.02Pa = 15.097lbf/in^2

the gage pressure does a skin diver experience when they dive to 35 ft is 15.097lbf/in^2

4 0
3 years ago
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