PLS HELP IM BEGGING YOU, i’ll give 15 points and brainliest to the right answer plsss. THE CHOICES ARE

Advanced Placement (AP)

2 answers:

Juliette [100K]3 years ago

6 0

Answer:

1 hr on problems and 3 reading

Explanation:

1 hr on problems bc he's able to finish 40 problems which is better than reading for 1 hr since the teacher said reading for 1 hr is equivalent to solving 35 problems. in the 2nd, 3rd and 4th hours he solves less than 35 problems each hour so it's better to just read for an hour.

nlexa [21]3 years ago

3 0

Answer:

1 hour working on problems, 3 hours reading.

Explanation:

According t to the TA's advice, Working 35 problems raises the score as much as reading the text for an hour. He gets the 35 problems done the first hour, (actually 40) but gets about half as effective with each passing hour. So spending the next Three hours reading would be more productive than working problems-- at least according to the data here.

I'd rather have the option to do problems for an hour, then read for an hour, then go back to working problems, then reading. Varied activities keep you from getting bored and unproductive.

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The graph of x^2=-2+y+5cosy is shown for y=11

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(a)

We have been given an equation $x^{2}=-2+y+5cosy$ . Upon taking derivative of this equation with respect to x on both the sides, we get:

$2x=0+\frac{dy}{dx}+5(-siny)\frac{dy}{dx}\\2x=(1-5siny)\frac{dy}{dx}\Rightarrow \frac{dy}{dx}=\frac{2x}{1-5siny}$

(b)

In order to write the equation of tangent line, we need to find the slope of the line. We know that point (3,11) lies on the graph. Therefore, we write the slope of the tangent as:

$\text{Slope}=\frac{dy}{dx}=\frac{2(3)}{1-5sin(11)}=1$

Therefore, equation of tangent line is:

$y-y_{1}=m(x-x_{1})\Rightarrow y-11=1(x-3)\\y-11=x-3\\y=x+8$

(c)

We know that slope of tangent is given as $\frac{dy}{dx}=\frac{2x}{1-5siny}$ . The tangent will be vertical when denominator of slope is zero, that is: